1 Two resistances R₁ = 50 N and R₂ = 40 A are connected with a battery of e.m.f 5 V and internal resistance 202 as shown in figure. A voltmeter of resistance 1000 2 is used to measure the potential difference across R₁. Find the percentage error is made in the reading. 1000 $2 www R₁=50 92 5 V 20 92 R₂-40 S2

icon
Related questions
Question
Two resistances R₁ = 50 2 and R,₂ = 40 NA are connected with
a battery of e.m.f 5 V and internal resistance 202 as shown
in figure. A voltmeter of resistance 1000 is used to measure
the potential difference across R₁. Find the percentage error is
made in the reading.
1000 Ω
R₁-50 92
5 V
20 92
ww
www
R₂-40 92
Transcribed Image Text:Two resistances R₁ = 50 2 and R,₂ = 40 NA are connected with a battery of e.m.f 5 V and internal resistance 202 as shown in figure. A voltmeter of resistance 1000 is used to measure the potential difference across R₁. Find the percentage error is made in the reading. 1000 Ω R₁-50 92 5 V 20 92 ww www R₂-40 92
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer