1. (3x - 2y + 1) dx + (3x - 2y + 3) dy = 0.

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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R Can you help me for my reviewer The topic: Bernoulli DE Give me the full solution for reviewing purposes thank you 1 and 3 only
1.
(3x - 2y + 1) dx + (3x - 2y + 3) dy = 0.
2. sin y(x + sin y) dx + 2x² cos y dy = 0.
dy/dx = (9x + 4y + 1)².
3.
5.
4. y' = y - xy³e-2x.
6.
7.
(3 sin y-5x) dx + 2x² cot y dy = 0.
8.
y'=1+6x exp (x - y).
9. dv/du = (u - v)² – 2(u - v) - 2.
10. 2y dx + x(x² In y − 1) dy = 0.
11. (ke2v - u) du = 2e²v (e²v + km) dv.
12. y' tan x sin 2y = sin² x + cos² y..
13. (x +2y-1) dx = (x +2y - 5) dy = 0.
y(x tan x + ln y) dx + tan x dy = 0.
14.
dy/dx = sin(x + y).
xy dx + (x² - 3y) dy = 0.
Transcribed Image Text:1. (3x - 2y + 1) dx + (3x - 2y + 3) dy = 0. 2. sin y(x + sin y) dx + 2x² cos y dy = 0. dy/dx = (9x + 4y + 1)². 3. 5. 4. y' = y - xy³e-2x. 6. 7. (3 sin y-5x) dx + 2x² cot y dy = 0. 8. y'=1+6x exp (x - y). 9. dv/du = (u - v)² – 2(u - v) - 2. 10. 2y dx + x(x² In y − 1) dy = 0. 11. (ke2v - u) du = 2e²v (e²v + km) dv. 12. y' tan x sin 2y = sin² x + cos² y.. 13. (x +2y-1) dx = (x +2y - 5) dy = 0. y(x tan x + ln y) dx + tan x dy = 0. 14. dy/dx = sin(x + y). xy dx + (x² - 3y) dy = 0.
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