1. 5x + 1 = 5x + 1 . Зх + 1 %3D Зх + 2 . 2x – 6x – 10 = -4x + 3 – 10 . x – 11x – 3 = -10x – 1 – 2 - 9x – 20 = 8x – 20 A. all real numbers B. no solution С. о &r - 20 . -x + 15 = x + 15

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter1: Basic Concepts And Properties
Section1.CR: Review Problem Set
Problem 67CR: A crime-scene investigator has 3.4 ounces of a sample. He needs to conduct four tests that each...
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match each equation in the first column with its solution in the second column. Items in the second column may be used more than once.

1. 5x + 1 = 5x + 1
. Зх + 1 %3D Зх + 2
. 2x – 6x – 10 = -4x + 3 – 10
. x – 11x – 3 = -10x – 1 – 2
- 9x – 20 = 8x – 20
A. all real numbers
B. no solution
С. о
&r - 20
. -x + 15 = x + 15
Transcribed Image Text:1. 5x + 1 = 5x + 1 . Зх + 1 %3D Зх + 2 . 2x – 6x – 10 = -4x + 3 – 10 . x – 11x – 3 = -10x – 1 – 2 - 9x – 20 = 8x – 20 A. all real numbers B. no solution С. о &r - 20 . -x + 15 = x + 15
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