1. A mixture consisting of 30 mL of waste and 270 mL of seeded dilution water has an initial Do of 8.55 mg/L; after 5 days, it has a final DO of 2.40 mg/L. Another bottle containing just the seeded dilution water has an initial DO of 8.75 mg/L and a final DO of 8.53 mg/L. Find the 5-days BOD of the waste.

1. A mixture consisting of 30 mL of waste and 270 mL of seeded dilution water has an initial Do of 8.55 mg/L; after 5 days, it has a final DO of 2.40 mg/L. Another bottle containing just the seeded dilution water has an initial DO of 8.75 mg/L and a final DO of 8.53 mg/L. Find the 5-days BOD of the waste.

Solid Waste Engineering

3rd Edition

ISBN:9781305635203

Author:Worrell, William A.

Publisher:Worrell, William A.

Chapter2: Municipal Solid Waste Characteristics And Quantities

Section: Chapter Questions

Problem 2.14P

See similar textbooks

Similar questions

A mixture consisting of 30 mL of waste and 270 mL of seeded dilution water has an initial DO of 8.55 mg/L; after five days, it has a final DO of 2.40 mg/L. Another bottle containing just the seeded dilution water has an initial DO of 8.75 mg/L and a final DO of 8.53 mg/L. Find the five-day BOD of the waste.
For a BOD analysis, 30 ml of waste with a DO of zero mg/L, is mixed with 270 ml of dilution water with a DO of 9 mg/L. The sample is then put in an incubator. The final DO is measured after 7 d. The final DO is measured at 3.0 mg/L. However, it is discovered that the incubator was set at 30°C. Assume a k1 of 0.2 d–1 (base e) at 20°C and θ = 1.05. Determine the 5 d, 20°C BOD of the sample
A test bottle containing just seeded dilution water has its DO level drop by 1.0 mg/L in a five-day test. A 300-ml BOD bottle just filled with 15 ml of wastewater and the rest seeded dilution water (sometimes expressed as a dilution of 1:20) experiences a drop of 7.2 mg/L in the same period. What would be the five day BOD of the waste?
A BOD test is run using 100 ml of treated waste H20 mixed with 200ml of pure water. The initial DO of the mixture is 9.0 mg/ml. After 5 days, Do id 4.0 mg/ml. What is the 5-day BOD of the waste water?
A standard BOD test is run using seeded dilution water. The blank bottle containing the seeded dilution water has an initial DO of 9.2 mg/L and a final DO of 8.2 mg/L. The waste sample is mixed with seeded dilution water at a 1:25 ratio. It has an initial DO of 9.0 mg/L and a final DO of 2.0 mg/L. Calculate the BOD5.
A writtine conclusion about solid waste, liquid waste and gastreous waste
Calculate the chemical composition of a typical yard waste with and without water (based on N and S). HINT: Assume 100 lb of waste, 40 % Moisture Content
A BOD analysis was begun on Monday. Fifteen ml of waste with a DO of zero was mixed with 270 mL of dilution water with a DO of 9 mg/L. The sample was then put in the incubator. Since the 5th day fell on a long weekend (Friday) and lab personnel do not work on Saturday, the final DO did not get measured until Monday, the eighth day. The final DO was measured at 2.8 mg/L. However, it was discovered that the incubator was mistakenly set at 32 ºC. Assume k is 0.15 day-1 at 20 ºC and θ= 1.05. Determine the 5-day 20 ºC BOD of the sample. Also, what is the ultimate CBOD at 32 ºC and 20 ºC; Will it vary?
A waste with a 5-day BOD (BOD)=200mg/L and k = 0.1 day¹ is discharged to a river at a rate of 1 m/s. The river has flow rate of 9 m/s and a background ultimate BOD (Lo) of 2 mg/L upstream of the discharge. (a) Calculate the ultimate BOD (Le) of the waste. (b) Furthermore, assuming instantaneous mixing after discharge, calculate Lo of the river water after it has received the waste. Ans.: (a) Ultimate BOD of wastewater = 508.3 mg/L, (b) Ultimate BOD of river water after discharge of waste-52.63 mg/L.
Q2 bHow can you determine chloride content in a waste water sample?
(a) Calculate the ultimate BOD of a waste that has a measured 5-day BOD of 20 mg/L, assuming a BOD rate coefficient of 0.15/day measured at 20 degrees C. (b) Estimate the rate coefficient if the temperature of the waste is raised to 30 degrees C. (c) What would be the BOD5 at 30 deg. C?
An air classifier is applied to separate a mixture of four solid waste components shown in Figure 5-20 above. All four components have equal mass.a) Determine the mass composition in percent of the four components in theoverflow (extract) if the air classifier is operated at an air velocity of 1,000 ft/min.b) Determine the mass composition in percent of the four components in theoverflow (extract) if the air classifier is operated at an air velocity of 2,000 ft/min