1. A sinusoidal wave form can be represented by the equation given below: 2nt v(t)=Vdc +Vp cos(wt+w) = V dc +Vp cos(2nft+q) = Vdc +Vp cos(+o T Amplitude = 0.50022 V Frequency = 10.000 KHz Period = 99.996 us Peak2Peak = 1.0052 DC RMS = 434.14 mV calculated he following quantities: Vdc, Vp, V pp , f,T, and w Use the time base (sec/div) and vertical section Volts/div) for all your calculations.

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.10MCQ: The average value of a double-frequency sinusoid, sin2(t+), is given by (a) 1 (b) (c) Zero
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1. A sinusoidal wave form can be represented by the equation given below:
2nt
v(t)=Vdc +Vp cos(wt+w) = V dc +Vp cos(2nft+w) = Vdc +Vp cos(+)
Amplitude = 0.50022 V
Frequency = 10.000 KHz
Period = 99.996 us
Peak2Peak = 1.0052
DC RMS = 434.14 mV
calculated he following quantities: V dc, Vp, Vpp , f, T,and o Use the time base (sec/div) and
vertical section Volts/div) for all your calculations.
Transcribed Image Text:1. A sinusoidal wave form can be represented by the equation given below: 2nt v(t)=Vdc +Vp cos(wt+w) = V dc +Vp cos(2nft+w) = Vdc +Vp cos(+) Amplitude = 0.50022 V Frequency = 10.000 KHz Period = 99.996 us Peak2Peak = 1.0052 DC RMS = 434.14 mV calculated he following quantities: V dc, Vp, Vpp , f, T,and o Use the time base (sec/div) and vertical section Volts/div) for all your calculations.
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