1. Althea saves $x each month; but in June she saved $4 more than twice her regular amount. In June she saved? 2. 3a (a + 2b) -b (2a – 3b) = 3. 5 (2x – y) – 2(3y – 5x) =
1. Althea saves $x each month; but in June she saved $4 more than twice her regular amount. In June she saved? 2. 3a (a + 2b) -b (2a – 3b) = 3. 5 (2x – y) – 2(3y – 5x) =
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter4: Polynomials
Section4.10: Problems Without Solutions
Problem 12P
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1. Althea saves $x each month; but in June she saved $4 more than twice her regular amount. In June she saved?
2. 3a (a + 2b) -b (2a – 3b) =
3. 5 (2x – y) – 2(3y – 5x) =
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