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1. An ACNHS athlete is doing a warm exercise in preparation for R1AA, he walks 8 km East, then 5 km South and finally 6 km West. Find the final displacement of the athlete.

1. An ACNHS athlete is doing a warm exercise in preparation for R1AA, he walks 8 km East, then 5 km South and finally 6 km West. Find the final displacement of the athlete.

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(Vector Resolution) Directions: Answer the following problems using the component method on a separate sheet of paper. Sample Problem: A spare fisherman happens to catch fish at the Cuenco Island, known for its good diving site and fish watching. He swims 2 m East, turns 3 m 400 North of East and finally moves 2.5 m North. What is the total displacement of the spare fisherman? Given: d1=2 m East; d2=3 m, 400 N of E; d3=2.5 m North; dr=? Solutions: a. Vector dx dy 2 m East 2 m 3 m (cos 40°) 2.31 m 3 m (sin 40°) 1.92 m 2.50 m 3 m, 400 N of E %3D %3D 2.5 m North Edx = 4.31 m Edy = 4. 42 m %3D b. Use the Pythagorean Theorem to solve for the total displacement. dr = /Cdx² + (Ed,)? dr = /(4.31 m)² + (4.42 m)² %3D V dr = v18.58 m² + 19.54 m² dr = v38.12 m² dr = 6.17 m c. To solve for the direction, 0 _Ed, – 4.42 px = 1.03 tan 0 %3D Σd 4.31 m e = tan-! = 460 dr = = 6.17 m, 46º N of E 1. An ACNHS athlete is doing a warm exercise in preparation for R1AA, he walks 8 km East, then 5 km South and finally 6 km West. Find the final displacement of the athlete. 2. One of the activities in Hundred Islands is parasailing which uses a speed boat. Mang Tony the driver of the speed boat drives 2.5 km due North of Marcos Island, then turns onto the open sea and continues in a direction 30° N of E for 1.5 km and finally turns 2.0 km due East. What is the total displacement of Mang Tony? 3. Ken leaves the office, drives 26 km due North, then turns onto a street and continues in a direction 30° N of East for 35 km and finally turns onto the highway due East for 40 km. What is his total displacement from the office?
Transcribed Image Text:(Vector Resolution) Directions: Answer the following problems using the component method on a separate sheet of paper. Sample Problem: A spare fisherman happens to catch fish at the Cuenco Island, known for its good diving site and fish watching. He swims 2 m East, turns 3 m 400 North of East and finally moves 2.5 m North. What is the total displacement of the spare fisherman? Given: d1=2 m East; d2=3 m, 400 N of E; d3=2.5 m North; dr=? Solutions: a. Vector dx dy 2 m East 2 m 3 m (cos 40°) 2.31 m 3 m (sin 40°) 1.92 m 2.50 m 3 m, 400 N of E %3D %3D 2.5 m North Edx = 4.31 m Edy = 4. 42 m %3D b. Use the Pythagorean Theorem to solve for the total displacement. dr = /Cdx² + (Ed,)? dr = /(4.31 m)² + (4.42 m)² %3D V dr = v18.58 m² + 19.54 m² dr = v38.12 m² dr = 6.17 m c. To solve for the direction, 0 _Ed, – 4.42 px = 1.03 tan 0 %3D Σd 4.31 m e = tan-! = 460 dr = = 6.17 m, 46º N of E 1. An ACNHS athlete is doing a warm exercise in preparation for R1AA, he walks 8 km East, then 5 km South and finally 6 km West. Find the final displacement of the athlete. 2. One of the activities in Hundred Islands is parasailing which uses a speed boat. Mang Tony the driver of the speed boat drives 2.5 km due North of Marcos Island, then turns onto the open sea and continues in a direction 30° N of E for 1.5 km and finally turns 2.0 km due East. What is the total displacement of Mang Tony? 3. Ken leaves the office, drives 26 km due North, then turns onto a street and continues in a direction 30° N of East for 35 km and finally turns onto the highway due East for 40 km. What is his total displacement from the office?
(Vector Resolution) Directions: Ansuwer the following problems using the component method on a separate sheet of paper. Sample Problem: A spare fisherman happens to catch fish at the Cuenco Island, known for its good diving site and fish watching. He swims 2 m East, turns 3 m 400 North of East and finally moves 2.5 m North. What is the total displacement of the spare fisherman? Given: d1=2 m East; d2=3 m, 400 N of E; d3=2.5 m North; dr=? Solutions: a. Vector 2 m East 3 m, 400 N of E dx 2 m 3 m (cos 40°) 2.31 m dy 3 m (sin 40°) = 1.92 m 2.50 m 2.5 m North Edx = 4.31 m Edy = 4, 42 m b. Use the Pythagorean Theorem to solve for the total displacement. dg = /Ed.j? + (Ed,)? dr = (4.31 m)² + (4.42 m)² dr = V18.58 m² + 19.54 m² dr = V38.12 m² dr = 6.17 m c. To solve for the direction, 0 4.42 - 1.03 Ed. 4.31 m tan 0 - e - tan-1 - 460 dg = 6.17 m, 46°N of E 1. An ACNHS athlete is doing a warm exercise in preparation for R1AA, he walks 8 km East, then 5 km South and finally 6 km West. Find the final displacement of the athlete.
Transcribed Image Text:(Vector Resolution) Directions: Ansuwer the following problems using the component method on a separate sheet of paper. Sample Problem: A spare fisherman happens to catch fish at the Cuenco Island, known for its good diving site and fish watching. He swims 2 m East, turns 3 m 400 North of East and finally moves 2.5 m North. What is the total displacement of the spare fisherman? Given: d1=2 m East; d2=3 m, 400 N of E; d3=2.5 m North; dr=? Solutions: a. Vector 2 m East 3 m, 400 N of E dx 2 m 3 m (cos 40°) 2.31 m dy 3 m (sin 40°) = 1.92 m 2.50 m 2.5 m North Edx = 4.31 m Edy = 4, 42 m b. Use the Pythagorean Theorem to solve for the total displacement. dg = /Ed.j? + (Ed,)? dr = (4.31 m)² + (4.42 m)² dr = V18.58 m² + 19.54 m² dr = V38.12 m² dr = 6.17 m c. To solve for the direction, 0 4.42 - 1.03 Ed. 4.31 m tan 0 - e - tan-1 - 460 dg = 6.17 m, 46°N of E 1. An ACNHS athlete is doing a warm exercise in preparation for R1AA, he walks 8 km East, then 5 km South and finally 6 km West. Find the final displacement of the athlete.
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