1. An electron initially moves in a horizontal direction and has a kinetic energy of 2 × 103 eV (electron- volts) when it enters to the electric field È as shown in the figure. It passes through a uniform electric field between two oppositely charged vertical plates to a field-free region with a velocity 2.8 × 10’m/s. The plates are separated from each other by a distance of 0.04 meter. Gravity is negligible. Calculate electric field and find its direction:
1. An electron initially moves in a horizontal direction and has a kinetic energy of 2 × 103 eV (electron- volts) when it enters to the electric field È as shown in the figure. It passes through a uniform electric field between two oppositely charged vertical plates to a field-free region with a velocity 2.8 × 10’m/s. The plates are separated from each other by a distance of 0.04 meter. Gravity is negligible. Calculate electric field and find its direction:
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![1. An electron initially moves in a horizontal direction
and has a kinetic energy of 2 × 103 eV (electron-
volts) when it enters to the electric field E as shown
in the figure. It passes through a uniform electric field
between two oppositely charged vertical plates to a
field-free region with a velocity 2.8 x 10'm/s. The
plates are separated from each other by a distance of
0.04 meter. Gravity is negligible.
0.04m
Electron
Calculate electric field and find its direction:
L
me = 9.11 x 10-31kg; qe = -1.6 × 10-1ºC;
1eV = 1.6 x 10¬19]
Hint:
1
Kinetic energy =
qE
mv²; Potential energy =
d
Use conservation of energy.
(A)5800 V/m; directed from R to L
(B) 5800 V/m; directed from L to R
(C) 6750 V/m; directed from R to L
(D)6750 V/m; directed L from to R
(E) None of them](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff580c0a6-b19b-4759-a31e-8ff765fb0fd7%2Fb75e3871-a2f3-4a65-af23-16741ecd6097%2Fuwhsa5o_processed.png&w=3840&q=75)
Transcribed Image Text:1. An electron initially moves in a horizontal direction
and has a kinetic energy of 2 × 103 eV (electron-
volts) when it enters to the electric field E as shown
in the figure. It passes through a uniform electric field
between two oppositely charged vertical plates to a
field-free region with a velocity 2.8 x 10'm/s. The
plates are separated from each other by a distance of
0.04 meter. Gravity is negligible.
0.04m
Electron
Calculate electric field and find its direction:
L
me = 9.11 x 10-31kg; qe = -1.6 × 10-1ºC;
1eV = 1.6 x 10¬19]
Hint:
1
Kinetic energy =
qE
mv²; Potential energy =
d
Use conservation of energy.
(A)5800 V/m; directed from R to L
(B) 5800 V/m; directed from L to R
(C) 6750 V/m; directed from R to L
(D)6750 V/m; directed L from to R
(E) None of them
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