1. Analysis of a Resistive Circuit using Ohms Law, KVL, and KCL Consider the series-parallel circuit in Figure 1: - Analyze the circuit with the switch open and compute the currents, 10, 11, 12, 13, and 15 and the voltages, VAC, VBA, VCB, and Voc. Enter the computed values into Table 4 a). Using the computed values in Table 4 a) complete Table 4 c). Analyze the circuit with the switch closed and compute the currents, Io, I₁, I2, I3, and 15 and the voltages, VAC, VBA, VCB, and VDC. Enter the computed values into Table 5 a). Using the computed values in Table 5 a) complete Table 5 c). I2 Vo S-Closed Io S-Closed R₁ C Table 5 a). Analysis Results D I₁ VAC/11 R₂ 12-13 + 15 Io 1₁ 12 13 (mA) (mA) (mA) (mA) R3- Figure 1: Series-parallel circuit to be analyzed and constructed. B VAB/12 13 Table 5 c). Computed from Analysis Results in Table 5 a) S-Closed VBC/13 S-Closed S-Closed S-Closed 10-11-12 15 15 (mA) R₁ = = 150Ω R₂ = 900 Vs R3 = 4020 Vo = 5V Vs = -5V VAC VBA VDC VCB (V) (V) (V) VAC+ VDA + VBD + VCB

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Please help analyze circuit with SWITCH CLOSED to compute current and voltage. 

1. Analysis of a Resistive Circuit using Ohms Law, KVL, and KCL
Consider the series-parallel circuit in Figure 1:
-
Analyze the circuit with the switch open and compute the currents, I0, I1, I2, I3, and I5
and the voltages, Vac, VBA, VCB, and Voc. Enter the computed values into Table 4 a).
Using the computed values in Table 4 a) complete Table 4 c).
Analyze the circuit with the switch closed and compute the currents, I0, I1, I2, I3, and
15 and the voltages, Vac, Vba, Vcâ, and Vòc. Enter the computed values into Table 5 a).
Using the computed values in Table 5 a) complete Table 5 c).
Vo
S-Closed
S-Closed
S-Closed
Table 5 a). Analysis Results
S-Closed
Io
S-Closed
+
S-Closed
R₁
C
D
1₁
12
ww
R₂
VAC/11
R3
Io I₁ 12 13
(mA) (mA) (mA) (mA)
Table 5 c). Computed from Analysis Results in Table 5 a)
VBC/13
VAB/12
B
Figure 1: Series-parallel circuit to be analyzed and constructed.
13
12−13+15 | 10-11-12
Is
+
R1 = 150Ω
R₂ = 900
Vs R3 4020
=
Vo = 5V
Vs = -5V
15 VAC VBA
(mA) (V)
VDC
VCB
(V) (V) (V)
VAC+ VDA + VBD + VCB
Transcribed Image Text:1. Analysis of a Resistive Circuit using Ohms Law, KVL, and KCL Consider the series-parallel circuit in Figure 1: - Analyze the circuit with the switch open and compute the currents, I0, I1, I2, I3, and I5 and the voltages, Vac, VBA, VCB, and Voc. Enter the computed values into Table 4 a). Using the computed values in Table 4 a) complete Table 4 c). Analyze the circuit with the switch closed and compute the currents, I0, I1, I2, I3, and 15 and the voltages, Vac, Vba, Vcâ, and Vòc. Enter the computed values into Table 5 a). Using the computed values in Table 5 a) complete Table 5 c). Vo S-Closed S-Closed S-Closed Table 5 a). Analysis Results S-Closed Io S-Closed + S-Closed R₁ C D 1₁ 12 ww R₂ VAC/11 R3 Io I₁ 12 13 (mA) (mA) (mA) (mA) Table 5 c). Computed from Analysis Results in Table 5 a) VBC/13 VAB/12 B Figure 1: Series-parallel circuit to be analyzed and constructed. 13 12−13+15 | 10-11-12 Is + R1 = 150Ω R₂ = 900 Vs R3 4020 = Vo = 5V Vs = -5V 15 VAC VBA (mA) (V) VDC VCB (V) (V) (V) VAC+ VDA + VBD + VCB
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