Examples are given as a guide. Thank you! Example 1. Suppose the mean amount of cholesterol inExample 2. A school has 800 senior high school students.eggs labeled “large" is 186 milligrams, with standardThe average height of these students is 65 in. with a standarddeviation 7 milligrams. Find the mean and variance for adeviation of 5 in. Suppose you draw a sample of 45 students.sample size of 100.Find the mean and standard deviation of the samplingGiven: µ = 186, a = 7, n= 100distribution.Solution:Given: N = 800, µu = 65, o = 5, n= 45Solution:A. Solving for sample meani = u = 186a. Solve for sample mean :I=μ= 65B. Solving for variance:o? 7?b. Solving for standard deviation49= 49100 1005. 800 – 45755=.11..97799N-nN-145800 –19=0.1067 ACTIVITY: Solve for the following1. Compute the mean and standard deviation of the sampling distribution of the sample mean when you plan to havea simple random sampling of size 64 from a population with mean of 44 and standard deviation of 16.2. Random samples of size 225 are drawn from a population with mean 100 and standard deviation 20. Find themean and variance of the sample mean.3. Random samples of size 64 are drawn from a population with mean 32 and standard deviation 5. Find the meanand variance of the sample mean.4. With the same distribution of young women's height where the mean is 52.5 inches and a standard deviation of6.25 inches, what will be your new sample mean and standard deviation for a sample size of 100?5. If a random sample of 81 are taken from a population with a mean (µ) of 5.75 and standard deviation of 1.02,then what will be the mean and variance of the sample mean.

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Examples are given as a guide. Thank you! Example 1. Suppose the mean amount of cholesterol inExample 2. A school has 800 senior high school students.eggs labeled “large&#34; is 186 milligrams, with standardThe average height of these students is 65 in. with a standarddeviation 7 milligrams. Find the mean and variance for adeviation of 5 in. Suppose you draw a sample of 45 students.sample size of 100.Find the mean and standard deviation of the samplingGiven: µ = 186, a = 7, n= 100distribution.Solution:Given: N = 800, µu = 65, o = 5, n= 45Solution:A. Solving for sample meani = u = 186a. Solve for sample mean :I=μ= 65B. Solving for variance:o? 7?b. Solving for standard deviation49= 49100 1005. 800 – 45755=.11..97799N-nN-145800 –19=0.1067 ACTIVITY: Solve for the following1. Compute the mean and standard deviation of the sampling distribution of the sample mean when you plan to havea simple random sampling of size 64 from a population with mean of 44 and standard deviation of 16.2. Random samples of size 225 are drawn from a population with mean 100 and standard deviation 20. Find themean and variance of the sample mean.3. Random samples of size 64 are drawn from a population with mean 32 and standard deviation 5. Find the meanand variance of the sample mean.4. With the same distribution of young women's height where the mean is 52.5 inches and a standard deviation of6.25 inches, what will be your new sample mean and standard deviation for a sample size of 100?5. If a random sample of 81 are taken from a population with a mean (µ) of 5.75 and standard deviation of 1.02,then what will be the mean and variance of the sample mean.

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