Being perpendicular just means that the dot product must equal zero, right? So dotting the two vectors and setting that = to zero would make this so, right?? 15-25¢ + 9-le =034-26¢ = oC= 34261,3076923076923-26-261. Find the value of k that will make the vectors v = <-1, -4, 2> and w = <5, k, 4>perpendicular to each other.-11-412).<5)ド、47=0<(-1:5) + (-4.k)+ (2.4)>-5 - 4K+8 =03-4 K =0- 4 K = - 3-4- 4K= 34rea of a parallelogram defined by PQ and QR when P = (4, 0, 1),R= (-2, -5, -3).(-3-0)=<-ネ,-2-3>-3),(1-2)-(-3.-7)>(-2 - 21)7wz W3o + 529678

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Answered: 1. Find the value of k that will make…

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1. Find the value of k that will make the vectors v = <-1, -4, 2> and w = <5, k, 4> perpendicular to each other. %3D

Trigonometry (MindTap Course List)

8th Edition

ISBN:9781305652224

Author:Charles P. McKeague, Mark D. Turner

Publisher:Charles P. McKeague, Mark D. Turner

Chapter7: Triangles

Section: Chapter Questions

Problem 1RP: We mentioned in Section 7.5 that our algebraic treatment of vectors could be attributed, in part, to...

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Being perpendicular just means that the dot product must equal zero, right? So dotting the two vectors and setting that = to zero would make this so, right??

15-25¢ + 9-le =0
34-26¢ = o
C= 34
26
1,3076923076923
-26
-26
1. Find the value of k that will make the vectors v = <-1, -4, 2> and w = <5, k, 4>
perpendicular to each other.
-11-412).<5)ド、47=0
<(-1:5) + (-4.k)+ (2.4)>
-5 - 4K+8 =0
3-4 K =0
- 4 K = - 3
-4
- 4
K= 3
4
rea of a parallelogram defined by PQ and QR when P = (4, 0, 1),
R= (-2, -5, -3).
(-3-0)=<-ネ,-2-3>
-3),(1-2)-(-3.-7)>
(-2 - 21)7
wz W3
o + 529
678

Quantities that have magnitude and direction but not position. Some examples of vectors are velocity, displacement, acceleration, and force. They are sometimes called Euclidean or spatial vectors.

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