1. For obtaining inert gases with very low oxygen partial pressures for laboratory research, one often passes these gases through a bed of copper turnings or titanium sponge, held at a high temperature. The residual oxygen reacts with the metal and leaves behind very low contents of oxygen. Normally the gas flow rate is so low that equilibrium conditions are assumed. Calculate the partial pressure of oxygen in a stream of argon gas after it is passed over copper at 650, 850 and 1050 K and suggest which temperature should be selected for best results. Please note that below 650 K, the kinetics may be too sluggish and the reaction may not come to equilibrium. Repeat your calculation for titanium sponge. 2 Cu (s)+ 0.5 O2 = Cu2O ΔGo = -162200+69.24 T Ti(s) + O2(g) = TiO2 (s) ΔGo = -937302 + 172.8 T

Introduction to Chemical Engineering Thermodynamics
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ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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1. For obtaining inert gases with very low oxygen partial pressures for laboratory research, one often passes these gases through a bed of copper turnings or titanium sponge, held at a high temperature. The residual oxygen reacts with the metal and leaves behind very low contents of oxygen. Normally the gas flow rate is so low that equilibrium conditions are assumed. Calculate the partial pressure of oxygen in a stream of argon gas after it is passed over copper at 650, 850 and 1050 K and suggest which temperature should be selected for best results. Please note that below 650 K, the kinetics may be too sluggish and the reaction may not come to equilibrium. Repeat your calculation for titanium sponge.

2 Cu (s)+ 0.5 O2 = Cu2O ΔGo = -162200+69.24 T

Ti(s) + O2(g) = TiO2 (s) ΔGo = -937302 + 172.8 T

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