1. For the function of three variables f(x, y, z) = sin(xy) + cos(yz) + tan(zx) calculate the partial derivative with respect to x, the partial derivative with respect to y and the partial derivative with respect to z

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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the differential of tanx is sec^2x so why is the partial derivative written as z(1+tan^2(zx)) ?

1. For the function of three variables f(x, y, z) = sin(xy) + cos(yz) + tan(zx) calculate the partial
derivative with respect to x, the partial derivative with respect to y and the partial derivative with respect
to z
SOLUTION: It is
of a sin(xy) + cos(yz) + tan(zx)
əx
əx
= y cos(yx) + 0 + z(1 + tan² (zx))
afa sin(xy) + cos(yz) + tan(zx)
ду
ду
af a sin(xy) + cos(yz) + tan(zx)
дz
дz
-= x cos(yx) - z sin(yz) + 0
0-ysin(yz) + x(1 + tan² (zx))
Transcribed Image Text:1. For the function of three variables f(x, y, z) = sin(xy) + cos(yz) + tan(zx) calculate the partial derivative with respect to x, the partial derivative with respect to y and the partial derivative with respect to z SOLUTION: It is of a sin(xy) + cos(yz) + tan(zx) əx əx = y cos(yx) + 0 + z(1 + tan² (zx)) afa sin(xy) + cos(yz) + tan(zx) ду ду af a sin(xy) + cos(yz) + tan(zx) дz дz -= x cos(yx) - z sin(yz) + 0 0-ysin(yz) + x(1 + tan² (zx))
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you did not answer my question. I want to know why the derivative of tan(zx) is written to be ztan^2(zx) instead of zsec^2(zx). the deriverative of tanx is secx^2, not tanx^2??

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