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A: Given: 1).limx→-1(7x4-x5+15x2-11) To solve the given…
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A: In this question we will use basic of calculus I.e concept of limits. Solution of the above question…
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A: 1)limx→2(2x-3)=1read : limit x tends to 2, (2x-3) is 1proof:limx→2(2x-3)=2(2)-3
Q: evaluate the limit.
A: Given it can be written as
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A: As per our guidelines we can solve only 1 question. The rest can be reposted. In question no 1…
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A: Note: According to our expert guidelines only first three subparts are to be answered kindly repost…
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A: We will solve the problem. L.Hospital Rule will be used in the problem.
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A: we have to solve given problem;
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Q: 1. lim (4x – 7) 2. lim (x3- 2x² + x - 5) X-1 3. lim (x2 - x + 3)(2x – 1) X-2
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A: 6. The limit does not exist. 9. The limit is, (- 1/8) The detailed solution is as follows below:
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- Find the limit of limitx->0= x2+4, x does not equal 0 = -1, x=01a. Find the limit. (If the limit is infinite, enter '∞' or '-∞', as appropriate. If the limit does not otherwise exist, enter DNE.) lim t-> -∞ ( (6t^2+t)/(t^3-7t+1)) 1b. Find the limit. (If the limit is infinite, enter '∞' or '-∞', as appropriate. If the limit does not otherwise exist, enter DNE.) lim u-> -∞ ((u^2+1)(8u^2-1)) /(u^2+9)^2 1c.Find the limit. (If the limit is infinite, enter '∞' or '-∞', as appropriate. If the limit does not otherwise exist, enter DNE.) lim x-> ∞ sqrt(x+6x^2)/(8x-1)Evaluate the Limits: a) limt->-1(t2+3t+2)/(t2-t-2) b) limx->9 (9x-x2)/(3-x1/2) c) limx->-inf (ex-e-x)/(ex+e-x) Do Not Use L'Hopital's Rule
- 1. Evaluate limx→2x2 + 5x + 1 using the Limit Laws. Show which laws you use at each step.2. Simplify, and then evaluate using the Direct Substitution Property: limx→1x2 + 2x − 3x2 + 6x − 7Use the limit process to find f'(x) = limh -->0 f(x+h) - f(x)/ h for f(x) = 3/4x-7.Find the limit.1. lim┬(x→-1)〖(2x^2-x-3)/(x+1)〗2 lim┬(h→0)〖(√(2+h)-√2)/h〗3. lim┬(x→5^+ )〖(x-5)/(x^2-25)〗4. lim┬(x→0^- )-〗〖3/x〗 5.lim┬(x→0)〖(-〖2x〗^3+3x-1)〗 6. lim┬(x→3)〖(x+1)/(x-3)〗 7.?(?)={?3 +3 ?≤2 ? > 2 lim┬?→2 ?(?)