1. Problem Description: The total nuclear binding energy is the energy required to split a nucleus of an atom in its component parts: protons and neutrons, or, collectively, the nucleons. It describes how strongly nucleons are bound to each other. When a high amount of energy is needed to separate the nucleons, it means nucleus is very stable and the neutrons and protons are tightly bound to each other. The atomic number or proton number (symbol Z) is the number of protons found in the nucleus of an atom. The sum of the atomic number Z and the number of neutrons N gives the mass number A of an atom. + Binding energy - Separated nucleons (greater mass) Nucleus (smaller mass) Figure 1: Binding Energy in the Nucleus The approximate nuclear binding energy Eb in million electron volts, of an atomic nucleus with atomic number Z and mass number A is calculated using the following formula: - azA3 – az1- a4° (A – 2Z)² ¸ a5 Eb = a,A – A A3 where, a, = 15.67,az = 17.23, az = 0.75, a4 = 93.2 ,and %3D

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1. Problem Description:
The total nuclear binding energy is the energy required to split a nucleus of an
atom in its component parts: protons and neutrons, or, collectively, the nucleons.
It describes how strongly nucleons are bound to each other. When a high amount
of energy is needed to separate the nucleons, it means nucleus is very stable
and the neutrons and protons are tightly bound to each other.
The atomic number or proton number (symbol Z) is the number of protons found
in the nucleus of an atom. The sum of the atomic number Z and the number of
neutrons N gives the mass number A of an atom.
+ Binding energy
Separated nucleons
(greater mass)
Nucleus
(smaller mass)
Figure 1: Binding Energy in the Nucleus
The approximate nuclear binding energy Eb in million electron volts, of an atomic
nucleus with atomic number Z and mass number A is calculated using the
following formula:
22
(А — 22)? , as
Eb = a,A – azA3 – az- a4-
A
A3
AZ
where, a,
15.67, az = 17.23, az = 0.75, a4 = 93.2 , and
%3D
%3D
1
Weights: 6%
Transcribed Image Text:1. Problem Description: The total nuclear binding energy is the energy required to split a nucleus of an atom in its component parts: protons and neutrons, or, collectively, the nucleons. It describes how strongly nucleons are bound to each other. When a high amount of energy is needed to separate the nucleons, it means nucleus is very stable and the neutrons and protons are tightly bound to each other. The atomic number or proton number (symbol Z) is the number of protons found in the nucleus of an atom. The sum of the atomic number Z and the number of neutrons N gives the mass number A of an atom. + Binding energy Separated nucleons (greater mass) Nucleus (smaller mass) Figure 1: Binding Energy in the Nucleus The approximate nuclear binding energy Eb in million electron volts, of an atomic nucleus with atomic number Z and mass number A is calculated using the following formula: 22 (А — 22)? , as Eb = a,A – azA3 – az- a4- A A3 AZ where, a, 15.67, az = 17.23, az = 0.75, a4 = 93.2 , and %3D %3D 1 Weights: 6%
if A is odd
if A and Z are both even
if A is even and Z is Odd
a5 =
12.0
(-12.0
The binding energy per nucleon (BEN) is calculated by dividing the binding
energy (Eb) by the mass number (A).
You are asked to write a program that requests the user for a valid atomic
number (Z) then goes through all values of A from A = Z to A = 4Z. For example,
if the user inputs 5 for Z then A will be all numbers from 5 (Z) to 20 (4 * Z)
inclusive, see the example output in figure 2.
If the user enters invalid atomic number that is not between 1 and 118, the
program should give the user another chance to enter a valid input as shown in
figure 2.
Your main task is to find the nucleus with the highest binding energy per nucleon,
which corresponds to the most stable configuration (figure 2), and writes a copy
of the table to a text file named output.txt (figure3).
In [25]: runfile('/Users/hamzazidoum/Documents/2101/2101_S2021/
Programming Assignments/PA4/pa4_nuclear.py', wdir='/Users/hamzazidoum/
Documents/2101/2101_S2021/Programming Assignments/PA4')
>>Enter valid atomic number (Z) (1,118]: 0
>>Enter valid atomic number (Z) (1,118]: -120
>>Enter valid atomic number (Z) (1,118]: 200
>>Enter valid atomic number (Z) (1,118]: 5
A
binding
energy
binding_ energy
per Nuc leon
5
-448.996
-226.623
-89. 799
-37.771
8.
9.
-82.990
-3.778
47.111
-11.856
-0.472
5.235
6.423
6.386
4.584
10
11
64.228
70.245
55.009
13
14
35.952
1.794
-32.682
-78.825
2.766
0.128
-2.179
-4.927
15
16
17
18
19
-123.453
-177.641
-229.307
-289.143
-7.262
-9.869
-12.069
20
-14.457
The most stable nucleus has a mass number 10
Figure 2: Sample run of the program
123 456 7 89e
5670o
Transcribed Image Text:if A is odd if A and Z are both even if A is even and Z is Odd a5 = 12.0 (-12.0 The binding energy per nucleon (BEN) is calculated by dividing the binding energy (Eb) by the mass number (A). You are asked to write a program that requests the user for a valid atomic number (Z) then goes through all values of A from A = Z to A = 4Z. For example, if the user inputs 5 for Z then A will be all numbers from 5 (Z) to 20 (4 * Z) inclusive, see the example output in figure 2. If the user enters invalid atomic number that is not between 1 and 118, the program should give the user another chance to enter a valid input as shown in figure 2. Your main task is to find the nucleus with the highest binding energy per nucleon, which corresponds to the most stable configuration (figure 2), and writes a copy of the table to a text file named output.txt (figure3). In [25]: runfile('/Users/hamzazidoum/Documents/2101/2101_S2021/ Programming Assignments/PA4/pa4_nuclear.py', wdir='/Users/hamzazidoum/ Documents/2101/2101_S2021/Programming Assignments/PA4') >>Enter valid atomic number (Z) (1,118]: 0 >>Enter valid atomic number (Z) (1,118]: -120 >>Enter valid atomic number (Z) (1,118]: 200 >>Enter valid atomic number (Z) (1,118]: 5 A binding energy binding_ energy per Nuc leon 5 -448.996 -226.623 -89. 799 -37.771 8. 9. -82.990 -3.778 47.111 -11.856 -0.472 5.235 6.423 6.386 4.584 10 11 64.228 70.245 55.009 13 14 35.952 1.794 -32.682 -78.825 2.766 0.128 -2.179 -4.927 15 16 17 18 19 -123.453 -177.641 -229.307 -289.143 -7.262 -9.869 -12.069 20 -14.457 The most stable nucleus has a mass number 10 Figure 2: Sample run of the program 123 456 7 89e 5670o
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