1. Processing of Examination Marks Marks obtained by a batch of students in the Annual Examination are tabulated as follows: Student name Marks obtained S.Laxmi V.S.Rao 45 67 38 55 77 89 56 69
1. Processing of Examination Marks Marks obtained by a batch of students in the Annual Examination are tabulated as follows: Student name Marks obtained S.Laxmi V.S.Rao 45 67 38 55 77 89 56 69
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
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![1. Processing of Examination Marks
Marks obtained by a batch of students in the Annual Examination are tabulated as follows:
Student name
Marks obtained
S.Laxmi
45 67 38 55
V.S.Rao
77 89 56 69
It is required to compute the total marks obtained by each student and print the rank list based on
the total marks.
The program in Fig.11.14 stores the student names in the array name and the marks in the array
marks. After computing the total marks obtained by all the students, the program prepares and
prints the rank list. The declaration
int
marks [STUDENTS] [SUBJECTS+1];
defines marks as a pointer to the array's first row. We use rowptr as the pointer to the row of
marks. The rowptr is initialized as follows:
int (*rowptr) [SUBJECTS+1] = array;
Note that array is the formal argument whose values are replaced by the values of the actual
argument marks. The parentheses around *rowptr makes the rowptr as a pointer to an array of
SUBJECTS+1 integers. Remember, the statement
int
*rowptr[SUBJECTS+1];
would declare rowptr as an array of SUBJECTS+1 elements.
When we increment the rowptr (by rowptr+1), the incrementing is done in units of the size of
each row of array, making rowptr point to the next row. Since rowptr points to a particular row,
(*rowptr)[x] points to the xth element in the row.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7c04c41b-ebed-4195-a62e-c3c68413f5c0%2Fe9596481-7276-4e33-9bce-1482eec27828%2Fhgi6x8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. Processing of Examination Marks
Marks obtained by a batch of students in the Annual Examination are tabulated as follows:
Student name
Marks obtained
S.Laxmi
45 67 38 55
V.S.Rao
77 89 56 69
It is required to compute the total marks obtained by each student and print the rank list based on
the total marks.
The program in Fig.11.14 stores the student names in the array name and the marks in the array
marks. After computing the total marks obtained by all the students, the program prepares and
prints the rank list. The declaration
int
marks [STUDENTS] [SUBJECTS+1];
defines marks as a pointer to the array's first row. We use rowptr as the pointer to the row of
marks. The rowptr is initialized as follows:
int (*rowptr) [SUBJECTS+1] = array;
Note that array is the formal argument whose values are replaced by the values of the actual
argument marks. The parentheses around *rowptr makes the rowptr as a pointer to an array of
SUBJECTS+1 integers. Remember, the statement
int
*rowptr[SUBJECTS+1];
would declare rowptr as an array of SUBJECTS+1 elements.
When we increment the rowptr (by rowptr+1), the incrementing is done in units of the size of
each row of array, making rowptr point to the next row. Since rowptr points to a particular row,
(*rowptr)[x] points to the xth element in the row.
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