_1. The Cartesian equation of the curve given in parametric equations x = e' – e-t , y = e' + e¬t is(a) x² – y² = 4.(c) x² – y² = 1.(d) y² – x² = 1.(b) y² – x² = 4._2. The equation of the tangent line to the curve x = -2t² + 3, y = t³ – 8t at the point where t = -2 is(a) x – 2y +7 = 0. (b) x + 2y – 7 = 0. (c) 2x – y + 7 = 0. (d) None of these._3. The slope m of the tangent line at any point on the curve r = 2 cos 0 is(b) – cot 20.(a) – tan 20.(c) tan 20.(d) None of these._4. The graph of the equation r² = 8 cos20 is a(a) limacon(c) circle(b) cardioid.(d) lemniscate._5. The distance between the points A(-2, –3,1) and B(6,9,-3) is(b) 2/14 units .(a) 4v14 units .(c) 8/14 units .(d) 4/7 units.

Name: _1. The Cartesian equation of the curve given in parametric equations
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Description: _1. The Cartesian equation of the curve given in parametric equations x = e' – e-t , y = e' + e¬t is(a) x² – y² = 4.(c) x² – y² = 1.(d) y² – x² = 1.(b) y² – x² = 4._2. The equation of the tangent line to the curve x = -2t² + 3, y = t³ – 8t at the po

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1. The Cartesian equation of the curve given in parametric equations x = et - e-t , y = e' + et is (a) x² – y? = 4. (d) y² – x² = 1. (b) y² – x² = 4. (c) x² - y? = 1.

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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