1. The electrical power p(t), in kilowatts, being used by a household as a function of time t, in hours, is modelled by a graph where t = 0 corresponds to 06:00. The graph indicated peak use at 08:00 and a power failure between 09:00 and 10:00. a) Determine p(0). b) Determine limp(t) 1-2 c) Determine lim p(t) and lim p(t). t-4 ↑p(t) 10- 0 06:00 N- Wo 12:00

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 44E
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1. The electrical power p(t), in kilowatts, being used by a household as a function of time t, in
hours, is modelled by a graph where t = 0 corresponds to 06:00. The graph indicated peak use
at 08:00 and a power failure between 09:00 and 10:00.
a) Determine p(0).
b) Determine limp(t)
t->2
c) Determine lim p(t) and lim p(t).
t-4+
t-4
↑p(t)
10-
6
0
06:00
2
3
4
12:00
Transcribed Image Text:1. The electrical power p(t), in kilowatts, being used by a household as a function of time t, in hours, is modelled by a graph where t = 0 corresponds to 06:00. The graph indicated peak use at 08:00 and a power failure between 09:00 and 10:00. a) Determine p(0). b) Determine limp(t) t->2 c) Determine lim p(t) and lim p(t). t-4+ t-4 ↑p(t) 10- 6 0 06:00 2 3 4 12:00
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