1. The following equation is solved for x. 3(x + 5) -5 = 20 Part A: Use the properties to justify the reason for each step in the chart below. Statements Reasons 3(x+5)-5 a. = 20 a. Given 3(x- b. 5-2*+5-5- = 20-5 b. c. 3(x+5)-5 = 100 c. d. 3x + 15 -5 = 100 d. e. 3x + 10 = 100 e. Equivalent Equation f. 3x + 10 - 10 = 100 - 10 f. g. 3x = 90 g. Equivalent Equation 90 3x h. h. i. Equivalent Equation i.x= 30
1. The following equation is solved for x. 3(x + 5) -5 = 20 Part A: Use the properties to justify the reason for each step in the chart below. Statements Reasons 3(x+5)-5 a. = 20 a. Given 3(x- b. 5-2*+5-5- = 20-5 b. c. 3(x+5)-5 = 100 c. d. 3x + 15 -5 = 100 d. e. 3x + 10 = 100 e. Equivalent Equation f. 3x + 10 - 10 = 100 - 10 f. g. 3x = 90 g. Equivalent Equation 90 3x h. h. i. Equivalent Equation i.x= 30
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter2: Linear Equations
Section2.1: Writing Equations
Problem 51PFA
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