1. The following integration can be solved by using the Substitution f 14 dx = ♦ (Choose the correct letter). A. 2ln+c B. 2+2 ln |x²|+c C. 2 In 1 + x²|+c D. 2 tan-¹+c E. None of these are correct 2. The following integration can be solved by using the fdx = ◆ (Choose the correct letter). A. 2 tan¹x+c B. 2 In 1+x+c C. 2 ln |1+x³ + c D. 2 tan-¹³ + c E. None of these are correct 3. The following integration can be solved by using the ◆ , and du= f 2x sinx dx = ♦ (Choose the correct letter), to get ♦ technique, where we have = → technique, where we have u technique, where we have = ◆ and du and du= du =
1. The following integration can be solved by using the Substitution f 14 dx = ♦ (Choose the correct letter). A. 2ln+c B. 2+2 ln |x²|+c C. 2 In 1 + x²|+c D. 2 tan-¹+c E. None of these are correct 2. The following integration can be solved by using the fdx = ◆ (Choose the correct letter). A. 2 tan¹x+c B. 2 In 1+x+c C. 2 ln |1+x³ + c D. 2 tan-¹³ + c E. None of these are correct 3. The following integration can be solved by using the ◆ , and du= f 2x sinx dx = ♦ (Choose the correct letter), to get ♦ technique, where we have = → technique, where we have u technique, where we have = ◆ and du and du= du =
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 68E
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