1. Water is flowing through a network of pipes (in thousands of cubic meters per hour), as illustrated in the diagram below. The direction of water flow is indicated by arrows, and pipe junctions are represented by the letters A, B, C, D, E, and F. A В з00 С х, 500 х, 500 D 450 E x, F *. The six linear equations for the flow rates x1, x2, X3, x4, x5 and æe are given by: + x3 = -500 = 500 - 2A = 300 = 300 - I5 = 300 - I5 = 300 (A) (B) = 50 Ts = 50 + x7 = 450 + a7 = 450 a5 - x6 + x7 = 0 2z + a6 - xT = 0 + x3 = 500 + x3 = 500 - x4 = 300 - x4 = 200 - I5 = 300 - I5 = 300 (D) F50 = 50 +#q= 450 +27 = 450 s - r+x7 = 0 az - 26 + x7 = 0 = 500 - 24 = 300 i+ 25 = 300 (E) = 50 + x7 = 450 a5 - a6 + x7 = 0

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 64E
icon
Related questions
Question
please do yourself and send correct answer
1. Water is flowing through a network of pipes (in thousands of cubic meters per hour), as
illustrated in the diagram below. The direction of water flow is indicated by arrows, and pipe
junctions are represented by the letters A, B, C, D, E, and F.
A
В з00 С х,
500
500
D 450 E X, F *.
The six linear equations for the flow rates x1, x2, X3, x4, x5 and x6 are given by:
+ x3
= -500
= 500
- 2A
= 300
= 300
- I5
= 300
- I5
= 300
(A)
(B)
= 50
= 50
+ x7 = 450
+ æ7 = 450
as - x6 + x7 = n
xz + x6 – x7 = 0
+ x3
= 500
+ x3
= 500
- C4
= 300
- x4
= 200
- x5
= 300
- x5
= 300
(C)
(D)
F 50
= 50
+ Xq= 450
+ x7 = 450
s - e +x7 = 0
az - 26 + 7 = 0
= 500
= 300
it *5
= 300
(E)
= 50
+ x7 = 450
x5 – x6 + x7 = 0
Transcribed Image Text:1. Water is flowing through a network of pipes (in thousands of cubic meters per hour), as illustrated in the diagram below. The direction of water flow is indicated by arrows, and pipe junctions are represented by the letters A, B, C, D, E, and F. A В з00 С х, 500 500 D 450 E X, F *. The six linear equations for the flow rates x1, x2, X3, x4, x5 and x6 are given by: + x3 = -500 = 500 - 2A = 300 = 300 - I5 = 300 - I5 = 300 (A) (B) = 50 = 50 + x7 = 450 + æ7 = 450 as - x6 + x7 = n xz + x6 – x7 = 0 + x3 = 500 + x3 = 500 - C4 = 300 - x4 = 200 - x5 = 300 - x5 = 300 (C) (D) F 50 = 50 + Xq= 450 + x7 = 450 s - e +x7 = 0 az - 26 + 7 = 0 = 500 = 300 it *5 = 300 (E) = 50 + x7 = 450 x5 – x6 + x7 = 0
Expert Solution
steps

Step by step

Solved in 3 steps with 2 images

Blurred answer
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage
Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
Algebra
ISBN:
9780395977224
Author:
Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:
McDougal Littell
Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
Algebra
ISBN:
9781285463247
Author:
David Poole
Publisher:
Cengage Learning
College Algebra
College Algebra
Algebra
ISBN:
9781337282291
Author:
Ron Larson
Publisher:
Cengage Learning
Elementary Linear Algebra (MindTap Course List)
Elementary Linear Algebra (MindTap Course List)
Algebra
ISBN:
9781305658004
Author:
Ron Larson
Publisher:
Cengage Learning
Algebra and Trigonometry (MindTap Course List)
Algebra and Trigonometry (MindTap Course List)
Algebra
ISBN:
9781305071742
Author:
James Stewart, Lothar Redlin, Saleem Watson
Publisher:
Cengage Learning