1. Write a program that calculates the result of z = xy a. The x and y variables should exist in memory after loading your program (use .FILL) b. Assume (6 >= x >= 0) and (6 >= y >= 0) C. Store the result of your exponential operation into the memory address x8000 and HALT your program
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please meet the following requiremtents using the LC3 simulator
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- In each of the following cases, write a short program in Vole to perform the requestedactivities. Assume that each of your programs is placed in memory starting at address 0x00.a. Move the value at memory location 0xD8 to memory location 0xB3.b. Interchange the values stored at memory locations 0xD8 and 0xB3.c. If the value stored in memory location 0x44 is 0x00, then place the value 0x01 in memorylocation 0x46; otherwise, put the value 0xFF in memory location 0x46(Practice) a. Using Figure 2.14 and assuming the variable name rate is assigned to the byte at memory address 159, determine the addresses corresponding to each variable declared in the following statements. Also, fill in the correct number of bytes with the initialization data included in the declaration statements. (Use letters for the characters, not the computer codes that would actually be stored.) floatrate; charch1=M,ch2=E,ch3=L,ch4=T; doubletaxes; intnum,count=0; b. Repeat Exercise 9a, but substitute the actual byte patterns that a computer using the ASCII code would use to store characters in the variables ch1, ch2, ch3, and ch4. (Hint: Use Appendix B.)a- Write a program which adds the values D8H, F5H and E9H. Put the sum in file register 15H for (low byte) and file register 16H for high byte. b- What is the content of (low byte) and (high byte) registers in Hex?
- Write an assembly program to set R0=1 if there's a 5 in one of ten memory locations, starting at x3100. At the beginning of the program, set R0 = 0. If no 5 is found, it should leave R0 set to 0. Please submit your assembly program below. I will run it with my data. If a 5 is found, output the following message to the console. "A 5 was found at x31xx." 31xx is the hex address of the 5. Here is the test data I used to generate the screen print below. It is not the test data I will use to grade your project. .ORIG x3100.FILL #10.FILL #20.FILL #30.FILL #40.FILL #50.FILL #5.FILL #70.FILL #5.FILL #90.FILL #100.ENDP1:Given the following memory values and a one-address machine with an accumulator,whatvalues do the following instructions load into the accumulator?·Word 20 contains 40.·Word 30 contains 50.·Word 40 contains 60.·Word 50 contains 70.a. LOAD IMMEDIATE 20b. LOAD DIRECT 20c. LOAD INDIRECT 20d. LOAD IMMEDIATE 30e. LOAD DIRECT 30f. LOADINDIRECT 30If the memory location at address 5 currently stores the value 8, what is the functional difference between writing the value 5 into cell number 6 and copying the contents of cell 5 into cell 6?
- Q2: Write program based on the following sequence of conditions: . Overwrite memory location $2800 with a value of $12345678 By using indirect addressing, copy a byte value in memory location $2000 into D3 by using address register A3. Increase value in D3 by $10.Write an assembly program to set R0=1 if there's a 5 in one of ten memory locations, starting at x3100. At the beginning of the program, set R0 = 0. If no 5 is found, it should leave R0 set to 0. Please submit your assembly program below. I will run it with my data. If a 5 is found, output the following message to the console. "A 5 was found at x31xx." 31xx is the hex address of the 5.Write a program to find the average of 32 bytes started at memory location [Mem 1]. If the average is greater than 42H then store the average at memory location [Mem 2] otherwise, store it at memory location [Mem 3].(microprocessor)
- Modify the following program in lc-3 to get the input(numbers) from the keyboard and print the result to console. .ORIG x3000Loop LD R0, number1 ; load number1 into R0LDR R1, number2 ; load number2 into R1ST R2, SaveR2 ; save register R2LD R5, goSUB ; load address of SUB into R4JSRR R5 ; go to subroutine whose address in R5STR R3, result ; store resultLD R2, SaveR2 ; restore old value R2HALTnumber1 .FILL #10number2 .FILL # -8goSUB .FILL SUB ; initialize goSUB to address of SUBSaveR2 .BLKW #1; reserve space SaveR2 and SaveR3result .BLKW #1SUB NOT R1, R1ADD R2, R1, #1ADD R3, R0, R2RET.ENDWrite programs that will accomplish the desired tasks listed below, using as few lines of code as possible e) Divide the data in RAM location 3EH by the number 12H ; put the quotient in R4 and the remainderin R5.f) Divide the data in RAM location 15H by the data in RAM location 16H ; put the quotient inexternal RAM location 7CH and the remainder in in external RAM location 7DH.g) Double the number in register R2, and put the result in register R3 (high byte) and R4 (low byte).Use logic operations.h) OR the contents of ports 1 and 2 ; put the result in external RAM location 0100Hi) Set Port 0, bits 1, 3, 5 and 7 to one, set the rest to zero.j) Clear bit 3 of RAM location 22H without affecting any other bit.k) Invert the data on the port 0 pins and write the data to port 1.Write a program to multiply the contents of the PINB by the contents of the RAM location 0x600 and store the lower and the higher bytes of the result in the RAM locations 0x500 and 0x501 simultaneously LDI R16, blank blank DDRB, R16 blank blank , PINB blank R16, blank blank R10, R16 blank 0x500, blank blank 0x501,