1. You may use the source code template in h3.s found in the assignment zip archive as a starting point. Let lower and upper be two positive integers with 1 ≤ lower, upper ≤ 10³ and lower ≤ upper. Let a and b be two positive integers with lower ≤ a,b ≤ upper and a ≤ b. Let x =ab. For all pairs of a and b satisfying the specified conditions, find and print the maximal value of x. For example, suppose lower = 10₁0 and upper = 1310. The algorithm will compute x for each a, b pair where 1010 max then max-x end for end for return max end function max_xor function main () unsigned int lower, max, upper SysPrintStr ("Enter lower? ") lower SysReadInt() SysPrintStr ("Enter upper? ") upper - SysReadInt () max max_xor (lower, upper) SysPrintInt (max) SysExit () end function main
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- Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print: 7 9 11 10 10 11 9 7 import java.util.Scanner; public class CourseGradePrinter {public static void main (String [] args) {Scanner scnr = new Scanner(System.in);final int NUM_VALS = 4;int [] courseGrades = new int[NUM_VALS];int i; for (i = 0; i < courseGrades.length; ++i) {courseGrades[i] = scnr.nextInt();} /* Your solution goes here */ P.S. The answer came out wrong the first try 7 9 11 10 10 11 9 7EnterBody of the Loop: A reasonable step would be: Choose some nodeu from foundNotHandled, and handle it. This involves following all the edges from u. Newly found nodes are now added to the set foundNotHandled (if they have notbeen found already). u is moved from foundNotHandled to foundHandled.Implement the LPU Latch my code is written below having a lot of bugs in it please give you code with proper comments and remove the bugs having proper reason with correct code: #include <bits/stdc++.h> using namespace std; class LRUCache { list dq; unordered_map<int, list<int>::iterator> ma; int csize; public: LRUCache(int); void refer(int); void display(); }; LRUCache::LRUCache(int n) { csize; } void LRUCache::refer(int x) { if (ma.find(x) == ma.end()) { if (dq.size() = csize) { dq.pop_back(); ma.erase(last); } } else dq.erase(ma[x]); dq.push_front(x); ma[x] = dq.begin(); } void LRUCache::display() { for (auto it = dq.begin(); it = dq.end(); it+) cout << (it); cout << endl; } int main() { LRUCache ca(4); ca.refer(1); ca.refer(2); ca.refer(3); ca.refer(1); ca.refer(4); ca.refer(5); return 0; }
- Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print: 7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = courseGrades.length - 1. import java.util.Scanner; public class CourseGradePrinter {public static void main (String [ ] args) {Scanner scnr = new Scanner(System.in);final int NUM_VALS = 4;int [ ] courseGrades = new int[NUM_VALS];int i; for (i = 0; i < courseGrades.length; ++i) {courseGrades[i] = scnr.nextInt();} /* Your solution goes here */ }}You are going to implement a program that creates an unsorted list by using a linked list implemented by yourself. NOT allowed to use LinkedList class or any other classes that offers list functions. It is REQUIRED to use an ItemType class and a NodeType struct to solve this. Use C++, please read instructions carefully and new solution only! The “data.txt” file has three lines of data 100, 110, 120, 130, 140, 150, 160 100, 130, 160 1@0, 2@3, 3@END You need to 1. create an empty unsorted list 2. add the numbers from the first line to list using putItem() function. Then print all the current keys to command line in one line using printAll(). 3. delete the numbers given by the second line in the list by using deleteItem() function. Then print all the current keys to command line in one line using printAll().. 4. putItem () the numbers in the third line of the data file to the corresponding location in the list. For example, 1@0 means adding number 1 at position 0 of the list. Then…You will also have to write Student Tests that test the following in the provided file.i. Adding element(s).ii. Get elements at index – (1) with a valid index and (2) with an invalid indexiii. Test equality of two StringArrayLists (of size 0, 2)iv. Test if a StringArrayList contains a String (test both true and false cases)v.Test removing a String from a StringArrayList.
- This problem has you write a nested loop to process a list of list of int, and accumulate a list of list of int. The starter code provides an accumulator for the result and a loop over the lists, and you need to write the code that checks whether sublist contains only even ints.You'll probably want a one-way flag: a Boolean variable that starts out as True and is set to False if you find an odd int in the sublist. You'll need to check the value of this variable to figure out whether to append sublist to the even_lists accumulator. from typing import List def only_evens(lst: List[List[int]]) -> List[List[int]]: """Return a list of the lists in lst that contain only even integers. >>> only_evens([[1, 2, 4], [4, 0, 6], [22, 4, 3], [2]]) [[4, 0, 6], [2]] """ even_lists = [] for sublist in lst: # write your code here (please read above for a suggested approach) return even_listsThis problem has you write a nested loop to process a list of list of int, and accumulate a list of list of int. The starter code provides an accumulator for the result and a loop over the lists, and you need to write the code that checks whether sublist contains only even ints. You'll probably want a one-way flag: a Boolean variable that starts out as True and is set to False if you find an odd int in the sublist. You'll need to check the value of this variable to figure out whether to append sublist to the even_lists accumulator. def only_evens(lst: list[list[int]]) -> list[list[int]]: """Return a list of the lists in lst that contain only even integers. >>> only_evens([[1, 2, 4], [4, 0, 6], [22, 4, 3], [2]]) [[4, 0, 6], [2]] """ even_lists = [] for sublist in lst: # write your code here (please read above for a suggested approach) return even_listsI'm trying to understand LargeIntList classes for lists, I was wondering these statements or True or False? either or, can you please explain your answers? Thank you. Uses the “by copy” approach with its elements. Implements the ListInterface interface. Keeps its data elements sorted. Allows duplicate elements. Uses the LLNode class of the support package. Throws an exception if an iteration “walks off ” the end of the list. Throws an exception if an element is added when it is "full". Supports addition of elements at the front of the list, the end of the list, and anywhere in between. Can hold objects of any Java class. Has only O(1) operations, including its constructor. Provides more than one Iterator.
- Stack CreateStack(S) push (S, 10) push (S, 15) push (S, 20) x = top (S) push (S, x + 5) x = pop (S) + top (S) push (S, x – pop (S)) push (S, pop (pop (S))) push (S, x – top (S)) push (S, push(S, x) – top (S)) After executing the given codes above, answer the questions and explain. ThanksDevelop a class ResizingArrayQueueOfStrings that implements the queueabstraction with a fixed-size array, and then extend your implementation to use arrayresizing to remove the size restriction.Develop a class ResizingArrayQueueOfStrings that implements the queueabstraction with a fixed-size array, and then extend your implementation to use arrayresizing to remove the size restriction.You are going to implement a program that creates an unsorted list by using a linked list implemented by yourself. NOT allowed to use LinkedList class or any other classes that offers list functions. It is REQUIRED to use an ItemType class and a NodeType struct to solve this homework. The “data.txt” file has three lines of data 100, 110, 120, 130, 140, 150, 160 100, 130, 160 1@0, 2@3, 3@END You need to 1. create an empty unsorted list 2. add the numbers from the first line to list using putItem() function. Then print all the current keys to command line in one line using printAll(). 3. delete the numbers given by the second line in the list by using deleteItem() function. Then print all the current keys to command line in one line using printAll().. 4. putItem () the numbers in the third line of the data file to the corresponding location in the list. For example, 1@0 means adding number 1 at position 0 of the list. Then print all the current keys to command line in one…