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1.4-5 A dramatically unstable way to calculate f(x) = e* for negative x is provided by its Taylor series (1.36). Calculate e*? by evaluating the Taylor series (1.36) at x = - 12 and compare with the accurate value e: = 0.00000 61442 12354 · · · . [Hint: By (1.36), the difference between e and the partial sum s, = 2x'/j! is less than the next term |x**/(n + 1)!| in absolute value, in case x is negative. So, it would be all right to sum the series until Sn+ 1) S. -

1.4-5 A dramatically unstable way to calculate f(x) = e* for negative x is provided by its Taylor series (1.36). Calculate e*? by evaluating the Taylor series (1.36) at x = - 12 and compare with the accurate value e: = 0.00000 61442 12354 · · · . [Hint: By (1.36), the difference between e and the partial sum s, = 2x'/j! is less than the next term |x**/(n + 1)!| in absolute value, in case x is negative. So, it would be all right to sum the series until Sn+ 1) S. -

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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1.4-5 A dramatically unstable way to calculate f(x) = e* for negative x is provided by its Taylor series (1.36). Calculate e1? by evaluating the Taylor series (1.36) at x = - 12 and compare with the accurate value e² = 0.00000 61442 12354 difference between e and the partial sum s, = 2;x'/j! is less than the next term |x**'/(n + 1)!| in absolute value, in case x is negative. So, it would be all right to sum the series until S, - Sn+1) · . [Hint: By (1.36), the
Transcribed Image Text:1.4-5 A dramatically unstable way to calculate f(x) = e* for negative x is provided by its Taylor series (1.36). Calculate e1? by evaluating the Taylor series (1.36) at x = - 12 and compare with the accurate value e² = 0.00000 61442 12354 difference between e and the partial sum s, = 2;x'/j! is less than the next term |x**'/(n + 1)!| in absolute value, in case x is negative. So, it would be all right to sum the series until S, - Sn+1) · . [Hint: By (1.36), the
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