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1.4.2 y(r)= Mar(1- r|,0) %3D to show this function is not a positive definite function we use definition 1 and set n = 3 we have 72 EEGMar(1 –| – 1,|.0) %3D i=1 j=l i=l j=l CIĞMar(1 – |21 – z1|.0) + GÓMar(1 – n- 2.0) + qĞMar(1 – n – 13| .0) +Qi Mar(1-|22 + 22Mar(1 =|22-12|.0) + cx&Mar(1 – |r2- 23|,0) + CxciAMar(1 –|13 – z1|,0) + CiMar(1– |13 – 12|.0) + Cx¢%Mar(1- |3- 13|,0) %3D -

1.4.2 y(r)= Mar(1- r|,0) %3D to show this function is not a positive definite function we use definition 1 and set n = 3 we have 72 EEGMar(1 –| – 1,|.0) %3D i=1 j=l i=l j=l CIĞMar(1 – |21 – z1|.0) + GÓMar(1 – n- 2.0) + qĞMar(1 – n – 13| .0) +Qi Mar(1-|22 + 22Mar(1 =|22-12|.0) + cx&Mar(1 – |r2- 23|,0) + CxciAMar(1 –|13 – z1|,0) + CiMar(1– |13 – 12|.0) + Cx¢%Mar(1- |3- 13|,0) %3D -

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 47RE
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Solve and find x's and c's such that answer will be less than zero
1.4.2 y(r) = Mar(1- r|,0) %3D to show this function is not a positive definite function we use definition 1 and set n = 3 we have 72 3 | i=l j=1 i=l j=l GĞMar(1 – |r1 – r1|.0) + c&Mar(1 – |n - 2).0) %! + cĞMar(1 – h - r3l .0) I3/,0) (o || + xÃMar(1 – |e2 - 21|.0) + cx5Mar(1= |22-12|.0) – |r2 - z3|,0) + Cxci Mar(1 –|r3- z1|,0) + CsMar(1- |23 – 12|,0) + Ca¢zMar(1– |r3 – 13|,0) + xgMar(1 Now we take common factors
Transcribed Image Text:1.4.2 y(r) = Mar(1- r|,0) %3D to show this function is not a positive definite function we use definition 1 and set n = 3 we have 72 3 | i=l j=1 i=l j=l GĞMar(1 – |r1 – r1|.0) + c&Mar(1 – |n - 2).0) %! + cĞMar(1 – h - r3l .0) I3/,0) (o || + xÃMar(1 – |e2 - 21|.0) + cx5Mar(1= |22-12|.0) – |r2 - z3|,0) + Cxci Mar(1 –|r3- z1|,0) + CsMar(1- |23 – 12|,0) + Ca¢zMar(1– |r3 – 13|,0) + xgMar(1 Now we take common factors
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