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10 80 psla 1.0 к, 0.1 0.01 0.1 10 Kcs ПT 1. ПL Distillate Component Ibmol/h iC4 пC4 iC5 пCs (12) 442 13 Feed Debutanizer Component Ibmol/h iC4 nCa (LK) ic5 (HK) (1) (468) 12 448 36 15 23 39.1 272.2 31.0 Св 876.3 Bottoms Component Ibmol/h 6 23 nC4 iC5 nC5 C6 (14) (23) (39.1) (272.2) (31.0) (408.3) Cg C9

10 80 psla 1.0 к, 0.1 0.01 0.1 10 Kcs ПT 1. ПL Distillate Component Ibmol/h iC4 пC4 iC5 пCs (12) 442 13 Feed Debutanizer Component Ibmol/h iC4 nCa (LK) ic5 (HK) (1) (468) 12 448 36 15 23 39.1 272.2 31.0 Св 876.3 Bottoms Component Ibmol/h 6 23 nC4 iC5 nC5 C6 (14) (23) (39.1) (272.2) (31.0) (408.3) Cg C9

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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For the debutanizer shown in Figure  and considered  estimate the Nmin by the Fenske equation. Assume a uniform operating pressure of 80 psia (552 kPa) throughout and utilize the ideal K-values given by Bachelor [4] as plotted in Figure.

10 80 psla 1.0 к, 0.1 0.01 0.1 10 Kcs ПT 1. ПL
Transcribed Image Text:10 80 psla 1.0 к, 0.1 0.01 0.1 10 Kcs ПT 1. ПL
Distillate Component Ibmol/h iC4 пC4 iC5 пCs (12) 442 13 Feed Debutanizer Component Ibmol/h iC4 nCa (LK) ic5 (HK) (1) (468) 12 448 36 15 23 39.1 272.2 31.0 Св 876.3 Bottoms Component Ibmol/h 6 23 nC4 iC5 nC5 C6 (14) (23) (39.1) (272.2) (31.0) (408.3) Cg C9
Transcribed Image Text:Distillate Component Ibmol/h iC4 пC4 iC5 пCs (12) 442 13 Feed Debutanizer Component Ibmol/h iC4 nCa (LK) ic5 (HK) (1) (468) 12 448 36 15 23 39.1 272.2 31.0 Св 876.3 Bottoms Component Ibmol/h 6 23 nC4 iC5 nC5 C6 (14) (23) (39.1) (272.2) (31.0) (408.3) Cg C9
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