10 cm 5 cm N = 8 turns AI = 5 A 10 V

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Q: 2) In a gravity controlled instrument, the deflecting torque corresponding to a deflection of 90° is…

A: Given: Deflecting torque, Td=1.2×10-4 kg-mθ=90°d=2 cm or 2×10-2 m

Q: 3. The torque applied to move the pointer is 279.8x10-6 N/m-1 and it creates the 0.859 Wbm-2…

A: Solution- Given data,Torque(τ) = 279.8 * 10-6 N/m-1Magnetic field intensity(B) = 0.8569 Wbm-2Area(A)…

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Q: 3. The torque applied to move the pointer is 355.6x10-6 N/m-1 and it creates the 0.598 Wbm2 magnetic…

A: Given: magnetic field density=.598 Wbm-2Voltage=26.5 VPower=288.3 mW

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Q: Q3\ The dimensions of the magnatic moving c 4cm*2.5cm ),number of turns is 60 ,the flux density…

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A: Given units are in CGS system Relunctance S = 0.06 N = turns = 2500 current I = 2.5 A

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Q: 14. An open coil has resistance and inductance. 15. The circuit element that oppose the change in…

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Q: 3. The torque applied to move the pointer is 355.6x106 N/m and it creates the 0.598 Wbm2 magnetic…

A: Given data, Applied torque is Td=355.6×10-6 Nm-1 Magnetic field density is B=0.598 Wbm-1 Area of…

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A: Here direction of B is given need to apply lenz law

Q: The torque applied to move the pointer is 279.8x10 N/m^-1 and it creates the 0.859 Wbm^-2 magnetic…

A: Given Data: T = 279.8 x 10-6  N/m B = 0.859 Wbm^-2  A = 0.055 cm x 0.125 m V = 21.9 V P = 286.9 mW

Q: . The torque applied to move the pointer is 355.6x10-6 N/m-1 and it creates the 0.598 Wbm-2 magnetic…

A: According to the question we have to i) calculate the total torque required to stop the pointer over…

Q: Consider the magnetic circuit given in below figure with parameters: u=105 Po, d1=7.2 cm, d2=6.6 cm,…

A: As filux in the series circuit is same , So, flux in airgap and central limb is same. We will find…

Q: Q1) The coil of a galvanometer has 100 turns, on a former that is 18 mm width of the coil 20mm,…

A: In this question , we will find deflection torque..