10 kPa B 0.4 m |+0.5 m++0.5 m++0.5 m+0.5 m- Soil A 1 m Exit Datum 0.75 m 0.5 m FIGURE P6.2
Q: n = 0.016 The rectangular-shaped channel has the best hydraulic cross-section. It is laid on a…
A: Given data - Roughness(n) = 0.016 Slope (S) = 0.0064 Discharge (Q) = 16.98 m³/s
Q: A 3.0m high embankment is to be constructed as shown. Determine the stress increase at P1. (49.81)…
A: Introduction- The embankment is an earthen material that is deposited and compacted to elevate the…
Q: A canal is excavated to a depth of 4 m below ground level in a soil having C = 15 kN/m², 3 = 18°,…
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Q: Determine hydraulic radius Wetted area=1.82 m2 Wetted perimeter=4.1 m
A: Introduction : The given question is related with fluid mechanics . In this question we are provided…
Q: The bottom width of a trapezoidal canal is 2.5m and its sides are both inclined at 60 degree with…
A: Given:- The bottom width of the trapezoidal canal = 2.5 m The inclination of the sides = 60 degrees…
Q: Home Work Check the stability of the gravity dam section shown in Figure at the section AA' assuming…
A: We have to check the stability of the gravity dam section shown in the figure according to the given…
Q: A 3.0m high embankment is to be constructed as shown. Determine the stress increase at P1. (49.81) D…
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Q: A canal having side slopes 1:1 is proposed to be constructed in a cohesive soil to a depth of 10 m…
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Q: H.W Example 2 Rising gradient 0.5 in 100
A: Rising gradients are written as Y:X where, Y is a rise and X is the run. Both numbers must have the…
Q: A trapezoidal channel section having base 8m, depth 4m and the hydraulic radius is 2.36m. the side…
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Q: Determine the critical depth for a rectangular smooth concrete flume (n=0.013) 4.5m wide which is to…
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Q: Water flows with a velocity of 3m/s, and a depth of 3 m in a rectangular channel of 2 m. Then there…
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Q: trapezoidal channel whose bottom width is 2.50 m . One side of the channel is vertical
A: In open channel flow hydraulic radius is defined as the ration of given cross section area to that…
Q: Q3). From the followings: St. 1: h=0.5m cut at center line, s = 4 assume right side higher than left…
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Q: Design a triangular open channel (n=0.014) that is anticipated to convey 25cumecs of water. The…
A: Given data: Triangular open channel n=0.014 Discharge=25 cumecs Slope=0.0015 It is asked to…
Q: trapezoidal concrete canal with slope 3H to 4V and bottom width 2m, the depth of flow is 2m and the…
A: Given Data:Slope = 3H to 4VBottom width = 2mdepth of flow = 2mslope = 3m/2kmn= 0.013
Q: A canal having side slopes 1:1 is proposed to be constructed in a cohesive soil to a depth of 10m…
A: Given data G = 2.65 Cu = 12 KPa e = 1 Sn = 0.08 H = 10 m F = Factor of safety
Q: H.W. 4 For a triangular channel having a side slope of Z horizontal: 1 vertical, Prove that: 20 Y. =…
A: The given data is shown below: Side slope=Z horizontal:1 vertical
Q: Situation: Two pipes are connected in parallel. L1 1200 m, D1 = 50 cm, L2 = 1500 m. D2 = 35 cm, Q =…
A: Given: L1 = 1200 m D1 = 50 cm = 0.5 m L2 = 1500 m D2 = 35 cm = 0.35 m Q = 1.2 m3/s
Q: A rectangular channel has a base width of 7 m and a depth of 2.5 m carries a discharge of 21.81 m…
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Q: 4. The hydraulic radius of a triangular section is 0.45m and the normal depth of the channel is 2m,…
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Q: What flow can be expected in a 1.2m wide rectangular, cement-lined channel (n=0.015) laid on a slope…
A: Given data width of channel (B) = 1.2 m depth of flow (y) = 0.6 m Slope (S) = 4m in 10km n = 0.015…
Q: A canal having side slope 1 to 1 is proposed to be constructed in a cohesive soil to a depth of 5 m…
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Q: A cutting is made in clay y=20kN/m³, ¤ =0, c = 35 kN/m². Take FOS= 1.5 and Sn = 0.17. Maximum depth…
A: Given data A cutting is in a clay soil. γclay = 20 KN/m3 ϕ = 0° C = 35 KN/m3 FOS = 1.5 Sn =…
Q: b. Lateral pressure due to soil (in kN/m2 per meter length of wall): @ point R = @ just above point…
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Q: A canal is proposed to be made in soil having cohesion 25 kN/m2, p' = 0° and void ratio of 0.792 and…
A: Given- Cohesion of soil C=25 kN/m2ϕ'=0ovoid ratio-e=0.792G=2.65Side slope=1:1FOS=2.5Stability no.…
Q: 4. Estimate the wetted area of a triangular channel having a depth of 5m and the side slope is…
A: We have to determine the value of wetted area of the given triangular channel section having depth…
Q: 1. A trapezoidal channel with a 5-m bottom width and side slope m = 1.0 discharges 35 m'/s. The…
A: The given trapezoidal channel has following characteristics: B=5 m m=1 S=0.004 n=0.012 Q=35 m3/s
Q: Red line in confined aquifer called إختر أحد الخيارات cone of depression A O Static water level BO…
A: A multiple choice questions have been given and it has been asked to select correct option. Please…
Q: trapezoidal channel section having base 8m, depth 4m and the hydraulic radius is 2.36m. the side…
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Q: • Q = 18 m^ 3 /s • Rectangular channel, 3 m wide • Unfinished form concrete channel • occurs at a…
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Q: 2. A trapezoidal canal section having side slope of 2H to 3V has a total depth of 1.5m. For a most…
A: Given data: Slope=2H to 3V Total depth=1.5 m It is asked find the bottom width of the most…
Q: 130 m 130 m 4.2 PE Sta 11+ 488 Elev 20.80 Lowest point 0.03 A 0.042 0.01 PT 0.30 m 0.95 m Invert
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Q: 4. A concrete channel which is laid on a slope of 1.9m per kilometer discharges water at a rate of 3…
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Q: A trapezoidal channel has a base of 1.5 m and 45-degree walls. A smooth asphalt lining (n = 0.015)…
A: OPEN CHANNEL FLOW:
Q: Check the over all stability for an earth dam with top width =8 m, height of dam=25m hw= 1.2m, u/s…
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Q: Determine the critical depth in meters for Trapezoidal channel. Base width = 5m Side Slope 2H:3V…
A: Critical depth is as below:
Q: The discharge through a trapezoidal 3 channel is 245.06m/s and the bed slope is 1 in 1000. Calculate…
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Q: Design an irrigation channel to carry 45 m^3/Sec of discharge. The channel is to be laid at a slope…
A: Given data, Discharge Q = 45 m3/s Slope S = 1/4000 Velocity ratio m = 1.1 Kutter's rugorsity…
Q: Example 3: Design a trapezoidal channel of water having a velocity 0.6 m/s, channel side slope…
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Q: This wood flume (n=0.012) has a slope of 0.0015. What will be the discharge of water in it for a…
A: Given:- n=0.012 slope = 0.0015 depth =1 m To find:- discharge of water
Q: The area of a channel section is 8m2 and the wetted perimeter is 8m. if the discharge is 33.33m/s…
A: Area A=8m2 Perimeter P=8m Discharge Q=33.33m3/ n=0.012
Q: Design a trapezoidal open channel (n=0.014) that is anticipated to convey 20cumecs of water. The…
A: Given Data:n=0.014Q=20 cumecsSlope=0.0015 It is required to design a trapezoidal open channel that…
Q: 8. Calculate the side slope of a trapezoidal channel section having base 8m, depth 4m and the…
A: This question is related to the open channel flow from Fluid Mechanics.
Q: H,0 1.1 m A B C ter is placed at point B, to what height the water will rlse above this point?
A: Pressure Head at B = ( 5.4 + 1.1 - 0.8m) = 5.1m Point Datum Head Pressure Head Total Heaf A…
Q: Design a channel section by Kennedy's theory given the following data : Discharge Q = 28 cumecs…
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Q: A trapezoidal channel with lower base 2.5m has a normal depth of water 1.2m. The sides of the…
A: Discharge in the channel is defined as the volume of water flow per unit time. The discharge of the…
Q: A concrete channel which is laid on a slope of 1.8m per kilometer discharges water at a rate of 2…
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Q: Design a semi-circular open channel (n=0.014) that is anticipated to convey 25cumecs of water. The…
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Q: 1. What flow can be expected in a 1.2m wide rectangular, cement - lined channel (n = 0.015) laid on…
A: Note:- Hi! Thank you for the question As per the honor code, We’ll answer the first question since…
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- A canal cut in rock (n — 0.030) is trapezoidal in section with a bottom width of 6.10 m and side slopes of 1 on 1. The allowable average velocity is 0.76 m/s. What slope will produce 5.66 m /s?A rectangular channel 4.59 m. wide by 1.35 m. deep is lined with a smooth stone (n = 0.014), well laid, and has a hydraulic slope of 0.0198. What would be the base (in meters) considering the most efficient proportion of the rectangular open channel? Round off to two decimal places.GEOTECHNICAL ENGINEERINGFor the clay slope, on rock determine the FS. If Kh = 0.4 (seismic factor)data H = 16 m β = 30 ° Ysat = 20 kn / m3 Cu = 50 kn / m2
- Find the velocity and discharge through a trapezoidal channel of 1.5 m wide and side slopesof 1.5 horizontal to 1 vertical. The depth of water is 1.2 m. Manning’s constant n = 0.025.The slope of bed of the channel is 1 in 2500A trapezoidal channel has a bottom section of 4.5m and a side slope of 1.5V:2H. Calculate the area.Find the required slope of a rectangular open channel when the water flows at a rate of 20,000 L/s, having a base width of 4m and depth water depth of 2.5m. (n = 0.013)
- A cement lined rectangular channel 6m wide carries water at the rate of 30m3/s. Find the value of Manning’s constant, if the slope required to maintain a depth of 1.5m is 0.00126422.A river 30m wide and 3m deep has stable bed and vertical banks with a surface slope of 1 in 2500. estimate the length of the back water curve produced by an afflux of 2m. assume n =0.035.HELP ASAP!!!! P: 4.5 kN , x: 10.8 m, y: 8.7 m
- a rectangular channel 4.61 m. wide by 1.48 m. deep is lined with a smooth stone (n = 0.019), well laid, and has a hydraulic slope of 0.018. what would be the base (in meters) considering the most efficient proportion of the rectangular open channel?The table below is the page of a level field book. 1) Calculate the difference in level between point A and G. 2) If it is required to build a horizontal embankment along the line AG, so that the elevation of the embankment is higher than the original ground surface with 150cm at point A. Calculate the depth of fill at point D. let RL of A=30m (all the readings in meter)A trapezoidal irrigation canal with side slope of 1.5 H to V is proposed to be lined with bricks to reduce seepage losses. It is required too carry a discharge of 20m ^ 2 / s of water. Find the wetted perimeter for minimum amount of lining and required bed slope. The value of Manning's Nis given as 0.015 and it is stipulated that average velocity cannot exceed 1 m/s.