10. The inverse of the elements of A = {0,1,2} under a*b = (a+b) modulo 3 areA. 0' = 0, 1' = 1, 2' = 2B. 0' = 1, 1' = 2, 2' = 0C. 0' = 0, 1' = 2, 2' = 1D. inverses does not exists10

Given : A={0,1,2} To Find : Inverses of A={0,1,2} under a*b=a+b (modulo 3)

Answered: 10.The inverse of the elements of A =…

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter3: Functions And Graphs

Section3.5: Graphs Of Functions

Problem 56E

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10.The inverse of the elements of A = {0,1,2} under a*b = (a+b) modulo 3 are A. 0' = 0, 1' = 1, 2' = 2 B. 0' = 1, 1 = 2, 2' = 0 C. 0' = 0, 1' = 2, 2' = 1 D. inverses does not exists