100 KN 60 kN 3m J G 4m 3m 40KN D 3m A Second Level: 100 KN 1.5m H B First Level: 100 KN 3m 60KN 1.5m 2 4V = 160 V = 40 KN 2V = 80 KN ..The horizontal reactions at A, B, and C are 40 kN, 80 kN, and 40 kN, respectively, all directed to the left. Calculate column moments, girder shears and moments and girder and column axial forces by dividing the frame into independent portals. Then draw the shear and moment diagrams of all girders and columns. V Let: ΣFv = 0: 2V + V + V = 100 4V = 100 V = 25 KN 2V = 50 kN 4m C 2V V V = shear at the exterior column 2V shear at the interior column

Structural Analysis
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Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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2. Analyze the given building frame.
100 KN
4m
4m
K
60 kN
40kN
3m
G
3m
2
4V = 160
V = 40 KN
2V = 80 KN
..The horizontal reactions at A, B, and C are 40 kN, 80 kN, and 40 kN,
respectively, all directed to the left. Calculate column moments, girder shears and
moments and girder and column axial forces by dividing the frame into independent
portals. Then draw the shear and moment diagrams of all girders and columns.
3m
Second Level:
100 KN
1.5m
H
First Level:
100 KN
3m
60KN
1.5m
T
B
V
Let:
ΣFv = 0:
2V + V + V = 100
4V = 100
V = 25 KN
2V = 50 kN
2V
V = shear at the exterior column
2V = shear at the interior column
EV
Transcribed Image Text:2. Analyze the given building frame. 100 KN 4m 4m K 60 kN 40kN 3m G 3m 2 4V = 160 V = 40 KN 2V = 80 KN ..The horizontal reactions at A, B, and C are 40 kN, 80 kN, and 40 kN, respectively, all directed to the left. Calculate column moments, girder shears and moments and girder and column axial forces by dividing the frame into independent portals. Then draw the shear and moment diagrams of all girders and columns. 3m Second Level: 100 KN 1.5m H First Level: 100 KN 3m 60KN 1.5m T B V Let: ΣFv = 0: 2V + V + V = 100 4V = 100 V = 25 KN 2V = 50 kN 2V V = shear at the exterior column 2V = shear at the interior column EV
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