100M Laura was asked to expand the expression log in terms of log M, log N, and constants. Laura's work/explanation: First I have to use the 2nd Log Law to turn the log of a quotient into a difference of logs: 100M log = log(100M) – log N² Now I have to use the 1st Log Law to turn the log of a product into a sum of logs: log 100 + log M - log N2 And finally I have to use the 3rd Log Law to turn the argument's exponent into the log's coefficient: log 100 + log M- 2 log N
100M Laura was asked to expand the expression log in terms of log M, log N, and constants. Laura's work/explanation: First I have to use the 2nd Log Law to turn the log of a quotient into a difference of logs: 100M log = log(100M) – log N² Now I have to use the 1st Log Law to turn the log of a product into a sum of logs: log 100 + log M - log N2 And finally I have to use the 3rd Log Law to turn the argument's exponent into the log's coefficient: log 100 + log M- 2 log N
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 27E
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