1010.10102 binary floating point to decimal floating point.
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- Convert 1010.10102 binary floating point to decimal floating point.
- Given the value -4.375
9a) Sign in binary is ________________
9b) Value to the left of the binary point, i.e., integral part in binary is ____________________
9c) Fractional part is _______________________________
SHOW ALL WORK ON HOW YOU OBTAINED THE FRACTIONAL PART.
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- Question P Both questions 5 a,b.and,c ) 5.A Convert the following unsigned binary numbers into the decimal form. a. 11 b. 1001 c. 10001 d. 1011001 B. Convert the following hexadecimal numbers into decimal form. a. AC b. DF0B c. 10B11 d. FDEAF1 C. Convert the following hexadecimal numbers into binary format. a. AC b. DF0B c. 10B11 d. FDEAF1 Full explain this question and text typing work only We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore this line. .Which one of the following represents the endian? Choose an answer A It is the ordering of bytes in a binary digits representation. B It contains swapped bytes. C The least shared memory in the word is occupied by its most significant binary number. D The word's lowest memory address is held by the least significant unit.1. a. Convert the following decimal integers in binary notation. You need to show your calculation as a sum of powers of two : 1609 1424 -33 (write in 8-bit two’s complement form) 1.b. Convert the binary integers in decimal notation. You need to show your calculation as a sum of powers of two as shown class: 11001012 10110112 110111012 (this binary number is in 8-bit two’s complement form)
- 1. Suppose (27.625 base 10) is represented using IEEE754 Single Precision Floating Point Format. What is the Mantissa? 2. Suppose (27.625 base 10) is represented using IEEE754 Single Precision Floating Point Format. What is the exponent? Choices: 11011101110111011011101000000000000000011011101000000000000000010000011011101100000000000000000017.33 Lab: Vectors: Binary to decimal conversion A binary number's digits are only 0's and 1's, which each digit's weight being an increasing power of 2. Ex: 110 is 1*22 + 1*21 + 0*20 = 1*4 + 1*2 + 0*1 = 4 + 2 + 0 = 6. A user enters an 8-bit binary number as 1's and 0's separated by spaces. Then compute and output the decimal equivalent. Ex: For input 0 0 0 1 1 1 1 1, the output is: 31 (16 + 8 + 4 + 2 + 1) Hints: Store the bits in reverse, so that the rightmost bit is in element 0. Write a for loop to read the input bits into a vector. Then write a second for loop to compute the decimal equivalent. To compute the decimal equivalent, loop through the elements, multiplying each by a weight, and adding to a sum. Use a variable to hold the weight. Start the weight at 1, and then multiply the weight by 2 at the end of each iteration. The assignment is to find main.cpp In C++ please. Very urgent. Your help is very much appreciated.MCQS the following? 1) .The number of bytes required to store single precision floating point numbers is a) 2 b) 4 c) 8 d) 16 2) The number of bytes required to store the variable "a", where a = [4 , 6 , -8, 13], would be a) 4 b) 8 c) 16 d) 32 e) 64
- 47 by -18 (integers in decimal (base 10)). Q1 : What is the remainder of the division in FP decimal representation (i.e., if rem=53 then its FP decimal representation is 53.0)? What is the resulting number if you shift it three digits to the right of the decimal point? Express your shifted result as a single precision FP number using the IEEE 754 standard for single precision. YOU MUST FIRST CONVERT THE NUMBER FROM BASE 10 to BASE 2 and then do normalization etc. Do not calculate more than the first 8 fraction bits.10. Fill in the following addition table for base 3.+ 0 1 201211. Identify the following statements as TRUE OR FALSE. a) BCD stands for Binary Coded Decimal and encodes each digit of a decimal number to an 8-bit binary form. b) Unicode is a 16-bit code, occupying twice the disk space for text as ASCII or EBCDIC would require. c) A signed-magnitude integer representation includes more negative numbers than it does positive ones. d) A byte is 8 bits, but a word may vary in size (16-bits, 32-bits, etc.) from one architecture to another. e)The largest value that a 60-bit unsigned binary integer can represent is (260-1). f) A 2's complement integer representation includes more negative numbers than it does positive ones.1. A CRC code uses the following generator: G = 0x225. Codewords have 8 data bits. (a) Write the binary representation of G. (b) Write the polynomial representation of G. (c) How many CRC bits are there in a codeword? (d) Calculate the corresponding codeword for the following information bits: 0010 0011. Please provide clear explanation
- 2. Convert the following binary numbers to floating point format. Assume a binary format consisting of a sign bit (negative = 1), a base 2, 8-bit, excess-128 exponent, and 23 bits of mantissa, with the implied binary point to the right of the first bit of the mantissa.a. 110110.011011b. −1.1111001c. 0.1100×236d. 0.1100×2−368. We have the following code word: 01111010101. This string has 7 data bits, plus 4check bits. We are using an error-correcting code that can correct single bit errors.In fact, there is a single bit error in this code. Assuming the use of the Hammingalgorithm, locate the bit that has been altered.Q.1) Mark the following statements as true or false and correct the second part if false: 1. The number (1.638125x235) expressed in IEEE 32-bit floating-point format as: 10010011 10100010000000000000000 2. The header of the CD-ROM format contains the block address and the mode byte, in which:-Mode 0 and Mode 1 : Blank data Field, Mode 2: use of an ECC. 3. When X=1.000000000000000000000000x21 and Y=1.111111111111111111111111x20, The result of (Z=X-Y) will be Z=1x2-20 without guard bits and Z=1x2-22 when adding four guard bits. 4. The simple interrupt cycle of control unit actually consists of 3 steps and 3 micro-operations. 5. In the instruction cycle sequence, after each execute cycle is a fetch cycle. 6. The Wilkes control technique is a horizontal microprogramming format. 7. After implementation Booth`s algorithm for the operation (7 * 3) the contents of registers: A=0001 and Q= 0101. 8. Double side hard disk drives have: 8 platters, and 128 sectors per track. When the size of…
