10kN 5kN/m 1m 2m 2m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Draw shear force and bending moment diagrams for the given simply supported beam.
![10kN
5kN/m
1m
2m
2m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3ca87274-7c17-4800-b6af-ce1173f2fc65%2F602afe8e-c517-49d2-86cc-c9215bb0b8f2%2Fbfgi36m.jpeg&w=3840&q=75)
Transcribed Image Text:10kN
5kN/m
1m
2m
2m
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Draw a free body diagram converting the UDL into a point load
As UDL is given 5kn and it is acting on the 2m length
Therefore, load will be 5 x 2 = 10 kN acting on center of 1m from point B.
![Civil Engineering homework question answer, Step 1, Image 1](https://content.bartleby.com/qna-images/answer/3ca87274-7c17-4800-b6af-ce1173f2fc65/b2461165-a9f1-44b2-9d3e-e5dfea092ae8/uev3vt.png)
Step 2
Take moments @A, we know the condition
Anticlockwise moment = clockwise moments
We know moment = force x perpendicular distance
RB x 5 = (10 x 1) + (10 x 4)
RB x 5 = 50
RB = 50/5= 10 kN.
Summation of upward force = summation of downward force
RA + RB = 10+10
RA + 10 = 20
RA = 20 – 10
RA = 10 kN
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