10x – 2 - dx . (x + 1)(5x² – 2x + 1) 16. Evaluate 5x - A) hx +1|+ n|5x² – 2x + 1|– tan +C 5x- B) Inx + 1|+ In|5x² – 2x + 1|+ tan — 1 +C 5x – C) Inx + 1|- In|5x – 2x + 1|+ tan 5х— 1 +C 2 5x – D) nx +1|- In|5x² – 2x + 1|– tan +C 2

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