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Rewrite the previous program by using while nested loop ? And the result must be as the following
1 2 3 4 5 6 7 8 9 10
11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30
31 32 33 34 35 36 37 38 39 40
41 42 43 44 45 46 47 48 49 50
51 52 53 54 55 56 57 58 59 60
61 62 63 64 65 66 67 68 69 70
71 72 73 74 75 76 77 78 79 80
81 82 83 84 85 86 87 88 89 90
91 92 93 94 95 96 97 98 99 100
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- Exercise H for the Nested Loop Nested Loop Problems Write the program that would generate the multiplication table for numbers 1 to 10. For example: Result 1 2 3 4 5 6 7 8 9 10 2 4 6 8 10 12 14 16 18 20 3 6 9 12 15 18 21 24 27 30 4 8 12 16 20 24 28 32 36 40 5 10 15 20 25 30 35 40 45 50 6 12 18 24 30 36 42 48 54 60 7 14 21 28 35 42 49 56 63 70 8 16 24 32 40 48 56 64 72 80 9 18 27 36 45 54 63 72 81 90 10 20 30 40 50 60 70 80 90100Write a C++ program that uses the following for loop: for ( int i = 0; i < e; i++ ) { for ( int j = 0; j < f; j++) cout << *(*(b+i) + j ) << “\t”; cout << endl;} To print the following multiplication table: 1 2 3 4 5 6 7 8 92 4 6 8 10 12 14 16 183 6 9 12 15 18 21 24 274 8 12 16 20 24 28 32 365 10 15 20 25 30 35 40 45 In your program, it is given that e = 5 and f = 9.I have a Python programming question: Write a program that prints all the even numbers divisible by 3 but not divisible by 7 between 1 and 200. Use while loop with continue statement. When the even number is divisible by 3 but not 7 continue statement should allow you to go into the next iteration of the loop without printing the number.Output:6 12 18 24 30 36 48 54 60 66 72 78 90 96 102 108 114 120 132 138 144 150 156 162 174 180 186 192 198
- Code in Python Write a function, print_integers_less_than(n), which takes an integer parameter n and prints each integer k which is at least 0 and is less than n, in ascending order. Hint: use a simple for loop. For example: Test Result print_integers_less_than(2) 0 1 print_integers_less_than(5) 0 1 2 3 4 print_integers_less_than(-3)Consider the following code: j = 3 while j < 10 : print("J has value ", j) After how many times does the loop stop?Write a program that asks user to input their first name. • Use for loop to print each letter of the first name • Additionally, the program should count number of letters in the name and should print 'number of letters in your first name is 7' (Sabrina) use the functions len() and print(f'....)
- Implement the following: 1) Use a loop to print all the numbers of multiples of 6 and multiples of 7 from 166 to 377 inclusive.2) Use a loop to print all the numbers of multiples of 6 and multiples of 7 from 377 to 166 inclusive. Example Output168, 210, 252, 294, 336,336, 294, 252, 210, 168, NEED HELP WITH PYTHONWrite a program using nested for loops that will print the table below exactly as shown: 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 You MUST use nested for loops to accomplish this. You MUST store the value printed in a variable. You cannot just print the values as a String like “10 11 12 13 14 ….” Questions What is the primary difference between how a while loop operates and how a do while loop operates? View the code below and indicate where each variable would have scope. (Circle all boxes for each variable in which that variable would be useable. class DoLittle { public static void main(String[] args) { int number =…Use Python Write a function, print_integers_less_than(n), which takes an integer parameter n and prints each integer k which is at least 0 and is less than n, in ascending order. Hint: use a simple for loop. For example: Test Result print_integers_less_than(2) 0 1 print_integers_less_than(5) 0 1 2 3 4 print_integers_less_than(-3)
- Add a loop over to this function that tracks how many times the sum functions is called. Also explain how the loop is working. int64_t sum(int64_t N, uint64_t A[]){ int64_t sum = 0; uint64_t indx = A[0]; for (int64_t i = 0; i < N; i++){ sum += A[indx]; indx = A[indx]; } return sum;}JAVA: Replace the for loop below with a code using the "While" loop: int s = 0; int c = 0; boolean valid = true; for(int i = 4; i <= 20 || valid; i = i+2) { if(i%4 != 0) { s = s + i; c++; } if(i > 20) { valid = false; } } System.out.println(s / c);Write a program that displays the following pattern of prime numbers using a nested for loop: 2 2 3 5 2 3 5 7 11 2 3 5 7 11 13 17 2 3 5 7 11 13 17 19 23
