11. -1 -3 دا دیا 4 - -2 4 0 1 3

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter4: Eigenvalues And Eigenvectors
Section4.3: Eigenvalues And Eigenvectors Of N X N Matrices
Problem 41EQ
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11 please step by step and write cl

4. Use this information to diagonalize A.
with eigenvalues 5, 3, and -2, and suppose you know that
= 3 is two-dimensional. Do you have enough information to
x
nalizable?
VI
6
5.
6.
2 2
13
1
1
1
1
426
0
-2
0
1
17
1
2
2:
1
2
0 -1
-1
0
0-2
5
0
=
5 0
IL:
2
1
0
0 0
=
4
5]
0 -15
1
I
0
0
0
0
5
0
0
1
0 0
1/4]
1/4 1/2
1/4 1/2 -3/4
1/4 -1/2 1/4]
E
eru
0
0
0
4
2
][/
-1
01
0
10
1 4
0-2
0
Diagonalize the matrices in Exercises 7-20, if possible. The
eigenvalues for Exercises 11-16 are as follows: (11) λ = 1,2, 3;
(12) λ = 2,8; (13) λ = 5, 1; (14) λ = 5, 4; (15) λ = 3,1; (16)
λ = 2,1. For Exercise 18, one eigenvalue is λ = 5 and one
eigenvector is (-2,1,2).
Transcribed Image Text:4. Use this information to diagonalize A. with eigenvalues 5, 3, and -2, and suppose you know that = 3 is two-dimensional. Do you have enough information to x nalizable? VI 6 5. 6. 2 2 13 1 1 1 1 426 0 -2 0 1 17 1 2 2: 1 2 0 -1 -1 0 0-2 5 0 = 5 0 IL: 2 1 0 0 0 = 4 5] 0 -15 1 I 0 0 0 0 5 0 0 1 0 0 1/4] 1/4 1/2 1/4 1/2 -3/4 1/4 -1/2 1/4] E eru 0 0 0 4 2 ][/ -1 01 0 10 1 4 0-2 0 Diagonalize the matrices in Exercises 7-20, if possible. The eigenvalues for Exercises 11-16 are as follows: (11) λ = 1,2, 3; (12) λ = 2,8; (13) λ = 5, 1; (14) λ = 5, 4; (15) λ = 3,1; (16) λ = 2,1. For Exercise 18, one eigenvalue is λ = 5 and one eigenvector is (-2,1,2).
4. Use this information to diagonalize A.
with eigenvalues 5, 3, and -2, and suppose you know that
= 3 is two-dimensional. Do you have enough information to
x
nalizable?
VI
6
5.
6.
2 2
13
1
1
1
1
426
0
-2
0
1
17
1
2
2:
1
2
0 -1
-1
0
0-2
5
0
=
5 0
IL:
2
1
0
0 0
=
4
5]
0 -15
1
I
0
0
0
0
5
0
0
1
0 0
1/4]
1/4 1/2
1/4 1/2 -3/4
1/4 -1/2 1/4]
E
eru
0
0
0
4
2
][/
-1
01
0
10
1 4
0-2
0
Diagonalize the matrices in Exercises 7-20, if possible. The
eigenvalues for Exercises 11-16 are as follows: (11) λ = 1,2, 3;
(12) λ = 2,8; (13) λ = 5, 1; (14) λ = 5, 4; (15) λ = 3,1; (16)
λ = 2,1. For Exercise 18, one eigenvalue is λ = 5 and one
eigenvector is (-2,1,2).
Transcribed Image Text:4. Use this information to diagonalize A. with eigenvalues 5, 3, and -2, and suppose you know that = 3 is two-dimensional. Do you have enough information to x nalizable? VI 6 5. 6. 2 2 13 1 1 1 1 426 0 -2 0 1 17 1 2 2: 1 2 0 -1 -1 0 0-2 5 0 = 5 0 IL: 2 1 0 0 0 = 4 5] 0 -15 1 I 0 0 0 0 5 0 0 1 0 0 1/4] 1/4 1/2 1/4 1/2 -3/4 1/4 -1/2 1/4] E eru 0 0 0 4 2 ][/ -1 01 0 10 1 4 0-2 0 Diagonalize the matrices in Exercises 7-20, if possible. The eigenvalues for Exercises 11-16 are as follows: (11) λ = 1,2, 3; (12) λ = 2,8; (13) λ = 5, 1; (14) λ = 5, 4; (15) λ = 3,1; (16) λ = 2,1. For Exercise 18, one eigenvalue is λ = 5 and one eigenvector is (-2,1,2).
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