11.2)question 11 continuous.9. 7(t) = (t²,1/t)10. 7(t) = (cost, e¹, In t)In Exercises 11-16, find the derivative of the given function.11. 7(t)= (cost, e¹, Int)1 2t-1t' 3t+1¹tant13. 7(t) = (t²) (sin t, 2t + 5)'14. r(t) = (²+1,t-1). (sin t, 2t + 5)15. 7(t) = (²+1,t-1, 1) × (sint, 2t +5,1)16. 7(t) = (cosh t, sinh t)In Exercises 17-20, find 7' (t). Sketch 7(t) and 7' (1), with theinitial point of 7' (1) at 7(1).17. 7(t) = (t + t,t²-t)12. 7(t)=35.36.29. Simplitsame a30. Simplifsame a31. Simplifysame as32. Simplifysame as i33.34.In Exercises 3integral.[(e.SI, COS11+1²(-sin t,[₁²2²(2t+1, 2

Given rt=cost,et,lnt We know that dcostdt=-sintdetdt=etdlntdt=1t

Answered: 11. 7(t) = (cost, e¹, Int)

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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