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12 Let A = 3 -8 -7 -8, We want to determine if the system Ax = b has a solution for every b e R³. Select the best answer. A. There is a not solution for every b ER³ but we need to row reduce A to show this. B. There is not a solution for every b E R³ since 2 < 3. C. There is a solution for every b E D. There is a solution for every b e R³ but we need to row reduce A to show this. E. We cannot tell if there is a solution for every b e R³. R3 since 2 < 3

12 Let A = 3 -8 -7 -8, We want to determine if the system Ax = b has a solution for every b e R³. Select the best answer. A. There is a not solution for every b ER³ but we need to row reduce A to show this. B. There is not a solution for every b E R³ since 2 < 3. C. There is a solution for every b E D. There is a solution for every b e R³ but we need to row reduce A to show this. E. We cannot tell if there is a solution for every b e R³. R3 since 2 < 3

Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter7: Distance And Approximation
Section7.2: Norms And Distance Functions
Problem 42EQ
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-3 12 Let A = 3 -8 -7 -8 We want to determine if the system Ax = b has a solution for every b e R3. Select the best answer. A. There is a not solution for every be R3 but we need to row reduce A to show this. B. There is not a solution for every be R³ since 2 < 3. C. There is a solution for every b eR³ since 2 < 3 D. There is a solution for every be R but we need to row reduce A to show this. E. We cannot tell if there is a solution for every b e R.
Transcribed Image Text:-3 12 Let A = 3 -8 -7 -8 We want to determine if the system Ax = b has a solution for every b e R3. Select the best answer. A. There is a not solution for every be R3 but we need to row reduce A to show this. B. There is not a solution for every be R³ since 2 < 3. C. There is a solution for every b eR³ since 2 < 3 D. There is a solution for every be R but we need to row reduce A to show this. E. We cannot tell if there is a solution for every b e R.
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