12) The solution of 2lnx-In(x+ 2)=In2 is a) 0 b) 1 c) {-1,4) d) 4 e) поп 13) sin( 2 csc"1(2)) = b) - a) d) 4 e) non 13x-1= 14) limx-1 1-3x a) -1 b) 1 c) -2 d) DNE e) non 15) limx--2 xt-16 x2+3x+2 %3D d) DNE e)non a) 32 c) 3 b) 1 Vx2+5 %3D 16) limy→-∞ 1–5x d) DNE e) non b) a) 116 115
12) The solution of 2lnx-In(x+ 2)=In2 is a) 0 b) 1 c) {-1,4) d) 4 e) поп 13) sin( 2 csc"1(2)) = b) - a) d) 4 e) non 13x-1= 14) limx-1 1-3x a) -1 b) 1 c) -2 d) DNE e) non 15) limx--2 xt-16 x2+3x+2 %3D d) DNE e)non a) 32 c) 3 b) 1 Vx2+5 %3D 16) limy→-∞ 1–5x d) DNE e) non b) a) 116 115
Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter7: Real And Complex Numbers
Section7.3: De Moivre’s Theorem And Roots Of Complex Numbers
Problem 4E: Show that the n distinct n th roots of 1 are equally spaced around a circle with center at the...
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Transcribed Image Text:12) The solution of 2lnx-In(x+ 2)= In2 is
a) 0
b) 1
c) {-1,4)
d) 4
e) пon
13) sin(2 csc"1(2)) =
a)
b)-
d) 4
e) non
13x-1=
14) limy-1
1-3x
a) -1
b) 1
c) -2
d) DNE
e) non
x2+3x+2
15) limx-2 xt-16
%3D
a) 32
c) 3
d) DNE
e)non
b) 1
Vx2+5
16) limy→-∞ 1–5x
%3D
d) DNE
e) non
b)
a)
116
115
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