12. A rancher uses 280 feet of fencing to build a rectangular corral for a horse. -280The length of the corral is 2.5 times the width. What is the area of the corral? 140 square feet © 4,000 square feet 76 B 700 square feet 16,000 square feet

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter4: Polynomials
Section4.9: Area Problems
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15
12
JUlutIon.
3x + 2.5 = 12x -5 x+9
3.
12. A rancher uses 280 feet of fencing to build a rectangular corral for a horse.
-28OThe length of the corral is 2.5 times the width. What is the area of the corral?
5.5
9.
140 square feet
© 4,000 square feet
5-276
700 square feet
D 16,000 square feet
l take
Transcribed Image Text:15 12 JUlutIon. 3x + 2.5 = 12x -5 x+9 3. 12. A rancher uses 280 feet of fencing to build a rectangular corral for a horse. -28OThe length of the corral is 2.5 times the width. What is the area of the corral? 5.5 9. 140 square feet © 4,000 square feet 5-276 700 square feet D 16,000 square feet l take
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