12. The area under the velocity vs time graph is supposed to be equal to the distance traveled along a straight line. Displacement = final position - initial position Distance: the distance traveled along the actual path. Since the average velocity = displacement (distance traveled along a straight line) / given time interval v = d/t d = vt Set the position of the man at -10.0 m, the velocity equal to 5 m's and the acceleration to 0.0. Run the simulation until the Moving Man hits the wall. What is the area under the velocity curve when the man reaches the +10 m mark? (You want velocity curve and the horizontal time axis. Realizing what kind of shape it is may help you calculate the area). Insert below a screen shot of the simulation for above description and your worksheet which shows how you obtain final answer for each question 39 seconds

12. The area under the velocity vs time graph is supposed to be equal to the distance traveled along a straight line. Displacement = final position - initial position Distance: the distance traveled along the actual path. Since the average velocity = displacement (distance traveled along a straight line) / given time interval v = d/t d = vt Set the position of the man at -10.0 m, the velocity equal to 5 m's and the acceleration to 0.0. Run the simulation until the Moving Man hits the wall. What is the area under the velocity curve when the man reaches the +10 m mark? (You want velocity curve and the horizontal time axis. Realizing what kind of shape it is may help you calculate the area). Insert below a screen shot of the simulation for above description and your worksheet which shows how you obtain final answer for each question 39 seconds