125mm Determine the maximum and minimum shearing 25mm stress developed in the web of the wide-flange section shown in the figure due to a shear force V=100 kN. Also compute the percentage of the 150mm 25mm vertical shear carried only by the web of the beam. 25mm

Q: Draw shear and moment diagram. Determine maximum moment and maximum shear. 25 KN/m 35 KN 60 KN.m…

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Q: 2. A hollow circular shaft of 6 m length and inner and outer diameters of 75mm and 100mm is…

A: Given data- Hollow circular shaft length (L) = 6 m Inner dia (di) = 75 mm Outer dia (do) = 100 mm…

Q: Draw the shear and bending moment diagrams for the reinforced concrete footing subjected to the…

A: Draw the free body diagram of the footing: Calculate the shear force at various locations:…

Q: Given: Maximum positive shear = 387.50 kN Maximum negative shear = 602.50 kN Maximum positive…

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Q: Determine the shear stress (in Mpa) in the 30.97-mm-diameter pin at B that support the beam if P =…

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Q: Calculate the reactions of supports for each beam below using forced method of analysis. 1. 20 kN /…

A: Static indeterminate structures can be analyzed using equilibrium equations and Compatability…

Q: Determine the maximum and minimum shearing stress in the web of the wide flange section in Fig. if V…

A: Given :- A flange beam section is given  Vertical shear force = 100 KN  To determine :-  a) Maximum…

Q: S0 kN 40 kn/m lo kN/m

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Q: Vith an evenly distributed superimposed load of 25 kN/m, a W420 x 85 steel beam is adequately…

A: The given data is: W420 x 85 steel beam with following properties:  UDL=25 kN/m,  A=10839.09…

Q: Determine the moment M in kN-m that must be applied to the beam to create maximum stress of 99 MPa.…

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Q: 20 KN 20 KN 200min 25 KN Im 100 mm 10 KN/m 10 KN/m B00 mm -1.00-T-00+ 4.00+1-001.00- 25mm -15m a.)…

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Q: 1. Determine the maximum and minimum shearing stress in the web of the wide flange section if V =…

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Q: unit across a 12-m. Determine the maximum shear in kN.

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Q: Determine the Maximum positive shear from the shear diagram. Attach here the shear diagram and…

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Q: Beam ABC with an overhang BC is subjectedto a linearly varying distributed load on spanAB with peak…

A: Given data:

Q: Q1/ 60 30 MM MM IF : N.A |= 27 * 10 mm 120 MM V= 19.5 KN Determine the maximum and minimum shearing…

A: in question 1   given dataI=27*106 mm4V=19.5KNy=60mm=NA shearing stress for T section is given…

Q: Find the shear force value at point 3 m from B

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Q: Determine sum of vertical support reaction at A and B

A: Given data : The value of point load P1=5 KNThe value of point load P2=4 KNTo find :Sum of vertical…

Q: Using area method. From the figure shown, 10 kN/m 10 kN/m 5 kKN/m B -3.0m- 12.0m- Figure 4 a. Draw…

A: ∑FX=0 HA=0 ∑FY=0 RA+RB=5×3+12×3×5+12×12×10....1 ∑MA=0…

Q: 1. Draw the shear and moment diagram. Determine the maximum shear and moment. 50 KN 150 kN - m' 15…

A: Firstly the support reactions in the beam should be calculated. Support reactions are shown in below…

Q: Q.5: A beam of channel section 120 mm x60 mm has uniform thickness of 15 mm. Determine the shear…

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Q: Situation 2: The section shown carries a shear force of 300 kN. 255 mm 20mm 330mm 15mm - 20mm 3.…

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Q: Determine the maximum torque of the tube shown if the allowable shearing stress is 56 Mpa. Given: t…

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Q: P kN В W kN/m 12 m A 5 m 5 m Draw the schematic / blown-up diagram of the frame showing the member…

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Q: The U-shaped beam is subjected to a shear force of 2.75 kN. Compute the shear stress 10 mm starting…

A: The given data is: Shear force, S=2.75 kN A1=40*30=1200 mm2 y1=302    =15 mm

Q: The maximum value of positive shear force that can be developed at point C in the beam shown below…

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Q: Draw the shear and moment diagram. | 12 kN 48 kN m B 41 a. Determine the shear value at 5 m from A.…

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Q: If the beam will be subjected to a shear force of V=190 kN, determine the shear stress at point H,…

A: Given, h=390 mm tw=12 mm d=100 mm t=8 mm V=190 kN A=2312 mm2 Iz=205150000 mm4   The section is…

Q: R Determine the axial force and moments at the top and bottom of the column below, 1.7P WDL =34 kN/m…

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Q: 5.52 Draw the shear and bending moment diagrams for the reinforced concrete footing subjected to the…

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Q: The steel beam has the cross-sectional area shown. if w = 6.5 kips/ft, determine the absolute…

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Q: Use the graphical method to construct the bending-moment diagram and identify the magnitude of the…

A: Consider the given figure. The vertical reaction at A is Ay=3.29 kN. The vertical reaction at D is…

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Q: For the beam below find the normal stress at sections in point (B) and (C) 75 kN 35 kN 45 kN 85kN…

A: T oFind :-  normal stress at B and C in sections of the beam

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Q: Determine the maximum bearing stress in MPa if P 115 kN. 20

A: The given data is: P=115 KN Ab=b*tmin tmin=25 mm b=452+452=63.63 mm     (bolt section=45*45)

Q: Draw shear and moment diagram. Determine maximum moment and maximum shear. 35 KN/m 50 KN 1.0 m 1.0…

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Q: P kN В W kN/m 12 m A 5 m 5 m Draw the schematic / blown-up diagram of the frame showing the member…

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Q: Given: Maximum positive shear = 387.50 kN Maximum negative shear = 602.50 kN Maximum positive…

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Q: Draw the shear and moment diagram. Determine the maximum shear and maximum mornent. P - 5 KN, W -2.5…

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Q: PROBUEM p. P2 2.5m 2 SM

A: RA+RB=6+12.5+12.5+10sinθRA+RB=39.4    →1

Q: If the T-beam is subjected to a vertical shear V = 14 kips, determine the maximum shear stress (ksi)…

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Q: Determine the moment M in kN-m that must be applied to the beam to create maximum stress of 98 MPa.…

A: Determine the moment M in kN-m that must be applied to the beam

Q: 7. The uniform 150-kg bar AB shown in Figure 5 carries a 2KN vertical force at A. the bar is…

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Q: Calculate: 2.1. The position of the horizontal centroidal axis of the cross-section from its bottom.…

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Q: * * a LL L1 b * с P * L2 d

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Q: 9 kN/m 9 kN/m B.

A: Given data:

Q: |10 kN 6 EN/m D. 15m-1.5 m-15 m-1.5m 300 N/m

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Q: Given: 40.5 P (kN) P (kN) 20 kN/m D E G t200m-+200 m- 3.00 m 2.00 m 1 m 2.00 m- 1 m a) Determine the…

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Q: 40.0 kN y 7.0 kN/m B 3 m 12 m 65.60 kN 58.40 kN 65.60 65.60 25,60 @x=6.66 m its: kN

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System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.