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13) Simplify the following Boolean function F, together with the don't-care conditions d, and then express the simplified function in sum-of-minterms form: (a) F(x, y, z) = 2(0, 1, 4, 5, 6) ( b), F (A, Β, C D) = Σ(0, 6, 8, 13, 14) %3D d (.y 2) - Σ(2,3,7) ( c) F(A , B, C D) = Σ(5, 6, 7, 12, 14, 15,) (d) F(Α, , CD) = Σ(4,12,7,2 , 10,) d(A, B, C, D) = £(3, 9, 11, 15) d(A, B, C, D) = £(2, 4, 10) d(A, B, C, D) = E(0, 6, 8) %3D

13) Simplify the following Boolean function F, together with the don't-care conditions d, and then express the simplified function in sum-of-minterms form: (a) F(x, y, z) = 2(0, 1, 4, 5, 6) ( b), F (A, Β, C D) = Σ(0, 6, 8, 13, 14) %3D d (.y 2) - Σ(2,3,7) ( c) F(A , B, C D) = Σ(5, 6, 7, 12, 14, 15,) (d) F(Α, , CD) = Σ(4,12,7,2 , 10,) d(A, B, C, D) = £(3, 9, 11, 15) d(A, B, C, D) = £(2, 4, 10) d(A, B, C, D) = E(0, 6, 8) %3D

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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13) Simplify the following Boolean function F, together with the don't-care conditions d, and then express the simplified function in sum-of-minterms form: ( a) F(x y z) = Σ(0,1,45, 6) d(x, y, z) = E(2, 3, 7) (b)* F(A, B, C, D) = E(0, 6, 8, 13, 14) %3D d(A, B, C, D) = £(2, 4, 10) (c) F(A, B, C, D) = E(5,6,7, 12, 14, 15,) (d) F(A, B, C, D) = E(4, 12, 7, 2, 10,) d(A, B, C, D) = E(3, 9, 11, 15) d(A, B, C, D) = £(0, 6, 8)
Transcribed Image Text:13) Simplify the following Boolean function F, together with the don't-care conditions d, and then express the simplified function in sum-of-minterms form: ( a) F(x y z) = Σ(0,1,45, 6) d(x, y, z) = E(2, 3, 7) (b)* F(A, B, C, D) = E(0, 6, 8, 13, 14) %3D d(A, B, C, D) = £(2, 4, 10) (c) F(A, B, C, D) = E(5,6,7, 12, 14, 15,) (d) F(A, B, C, D) = E(4, 12, 7, 2, 10,) d(A, B, C, D) = E(3, 9, 11, 15) d(A, B, C, D) = £(0, 6, 8)
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