Question
Asked Oct 16, 2019
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Find the derivative of the function

1)3
(t +1)2/3(212-
19. h(t) =
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1)3 (t +1)2/3(212- 19. h(t) =

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Expert Answer

Step 1

We know that,

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Product rule: y f(x)g(x) then y' f'(x)g(x)f(x)g'(x)

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Step 2

Given,

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h(t) (t1)2/3(2t2 1)3

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Step 3

Now differentiating on both sides with respe...

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2 d[(t+1)3(2t2-1)3] dh(t) = dt dt 2 h'(t) (2t2 1)3 d(t+1)ā + (t + 1) 2t2-1)3 dt dt = (2t2 - 1) x(t1)i(1) + (e + 1) x 3(2t2 - 1)3-1 x (4t) (1)t1 x 3(2t2 - 1)3-1 x (4t) (2t2 1)(t1)12t(t + 1) (2t2 - 1) 3 1 2(2t2 1) (2t2 - 1)(t 1)6t(t 1) (2t2-1) 2 = 2(2t2 - 1)2(2 6t(t1) 3 (t+1)3

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Tagged in

Math

Calculus

Derivative