13. 2xy dx + y“dy= 0; y(0) = 1. Answer: [2r² + y² = 1]

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Solve the following Non-exact DE using INTEGRATING FACTORS.

13. 2xy dx + y*dy = 0; y(0) = 1.
Answer: [2r² + y² = 1]
14. (2xy³ + y*) + (xy³ – 2y) y' = 0; y(1) =-1.
Answer: [x? + xy + 2/y = 2]
Transcribed Image Text:13. 2xy dx + y*dy = 0; y(0) = 1. Answer: [2r² + y² = 1] 14. (2xy³ + y*) + (xy³ – 2y) y' = 0; y(1) =-1. Answer: [x? + xy + 2/y = 2]
Determine the solution the following non-exact
differential equations:
8. (y + 1)dx – xdy = 0.
Answer: [(y + 1)/x = C]
9. (x*y – y)dx –xdy = 0.
Answer: [r² – In (xy)² = C]
10. (y +x³ + xy²)dx – xdy = 0.
Answer: [x² + 2Arctan (y/x) = C]
11. 2xy + y* + (xy³ – 2y)y' = 0.
Answer: [x + xy + 2/y = C]
12. xy'dx = (x + xy²)dy.
Answer: [x? – y? + In y² = C]
LECTURE NOTES ONLY – 1ST SEM 2021-2022
15. sin y cos x dy – sin x cos y dx = 0, y(0) = T.
Answer": [cos x / cos y = -1]
16. Sketch the graph of #37.
17. Sketch the graph of #38.
Transcribed Image Text:Determine the solution the following non-exact differential equations: 8. (y + 1)dx – xdy = 0. Answer: [(y + 1)/x = C] 9. (x*y – y)dx –xdy = 0. Answer: [r² – In (xy)² = C] 10. (y +x³ + xy²)dx – xdy = 0. Answer: [x² + 2Arctan (y/x) = C] 11. 2xy + y* + (xy³ – 2y)y' = 0. Answer: [x + xy + 2/y = C] 12. xy'dx = (x + xy²)dy. Answer: [x? – y? + In y² = C] LECTURE NOTES ONLY – 1ST SEM 2021-2022 15. sin y cos x dy – sin x cos y dx = 0, y(0) = T. Answer": [cos x / cos y = -1] 16. Sketch the graph of #37. 17. Sketch the graph of #38.
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