(14) = (x – y + 5)? dx dy %3D dy (15) (x² – y²)" – xy = 0 dx dy (16) 2xy = x² + 2y² %3D dx

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Substitution Method
dy
(14) = (x – y + 5)²
dx
(15) (x² – y²) – xy = 0
(16) 2xy = x² + 2y²
-
dx
dx
Transcribed Image Text:Substitution Method dy (14) = (x – y + 5)² dx (15) (x² – y²) – xy = 0 (16) 2xy = x² + 2y² - dx dx
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