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(15) 5.00 _d²_ dx x²+ 100 = 5.00 _d² + dx - 2 X +100 = lim 848 = lim 848 b = lim Sa dx + lim so dx 948 x² + 10² b→∞ + [ lo So di dx = 1 b So de + lim so de dx a x² +100 640 x + 100 = 1 x + 100 I tam' x 10 -] 10 | a [ +++] 10 2 2 + lim I tan! •÷ [(*)-(+)] lim tan x 'lim tam' x 10 10 a b→∞0 10 o- lim tom' a + lim tam' b a-8 b→∞ 10 10 O - O s dx = ____ tan't a Lom trying to understand why tań" (00) = I/I

(15) 5.00 _d²_ dx x²+ 100 = 5.00 _d² + dx - 2 X +100 = lim 848 = lim 848 b = lim Sa dx + lim so dx 948 x² + 10² b→∞ + [ lo So di dx = 1 b So de + lim so de dx a x² +100 640 x + 100 = 1 x + 100 I tam' x 10 -] 10 | a [ +++] 10 2 2 + lim I tan! •÷ [(*)-(+)] lim tan x 'lim tam' x 10 10 a b→∞0 10 o- lim tom' a + lim tam' b a-8 b→∞ 10 10 O - O s dx = ____ tan't a Lom trying to understand why tań" (00) = I/I

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I am trying to understand why is tan^-1(∞) = π/2

(015) 5.00 : 5.00 dr dx 2 x + 100 10 2 X + 100 lim a →∞0 10 = 1 b = lim Sa dx + lim So do dx a →∞ X + 100 b + lim so b→∞ 10 + = lim So dx + lim a48 x² +10² *+[.. lo 00 5.⁰⁰ O dx 2 x + 100 2 x + 100 640 [[|] + lim b→∞0 10 tam x I + I 2 10 | a dis dx x + 10 tan_ [(²)(²+1)] 'lim tan x lim 10 a tan 。- lim tam' a + lim tan b b→∞ a →∞0 10 O b 10 O S do = I tom' I dx x² + a² a a Lom trying to understand why tań" (co) = III am 2
Transcribed Image Text:(015) 5.00 : 5.00 dr dx 2 x + 100 10 2 X + 100 lim a →∞0 10 = 1 b = lim Sa dx + lim So do dx a →∞ X + 100 b + lim so b→∞ 10 + = lim So dx + lim a48 x² +10² *+[.. lo 00 5.⁰⁰ O dx 2 x + 100 2 x + 100 640 [[|] + lim b→∞0 10 tam x I + I 2 10 | a dis dx x + 10 tan_ [(²)(²+1)] 'lim tan x lim 10 a tan 。- lim tam' a + lim tan b b→∞ a →∞0 10 O b 10 O S do = I tom' I dx x² + a² a a Lom trying to understand why tań" (co) = III am 2
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