15" Consider the series Evaluate the the (n + 1)62n+1 n=1 following limit. If it is infinite, type "infinity" or "inf". If it does not exist, type "DNE". An+1 lim L an Answer: L What can you say about the series using the Ratio Test? Answer "Convergent", "Divergent", or "Inconclusive". Answer: choose one O Determine whether the series is absolutely convergent, conditionally convergent, or divergent. Answer "Absolutely Convergent", "Conditionally Convergent", or "Divergent". Answer: choose one

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A: We can find the radius of convergence by using the ratio test.

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Q: 1. Determine whether the series converges or diverges. State which test you use. sin n n2 + 4 n=1

A: Test whether the series is convergence or divergent

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A: We are given the series ∑n=1∞15n(n+1)82n+1. Here, an=15n(n+1)82n+1. So, an+1=15n+1(n+2)82n+3. Now,…

Q: There

A: ,We know that, ∑n=0∞1np is converges for all p&gt;1.i.e.∑n=0∞1npis converges for all p&gt;1. This…

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Q: Σ(5+, the series n= 1 converges by using : Select one: a. root test b. telescoping series c. the…

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Q: 6 Σ. n+sin(n 100 m=1 n2+100,000

A: note  series ∑n=11np is convergent if and only if p&gt;1

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A: Given the series ∑n=1∞ an     where an = 4n-4n2n+42n     To Compute: L = limn→∞ ann