15. 15. Explain how a stack is used to evaluate the RPN expressions from Exercise 13. 1. a) 12 8 3 1 + -/ 2. b) 5 2+2 x 1 + 2x 3. c) 357+21-X 1++
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- 4. a) Using the stack diagram, convert the following infix expression to a postfix expression. A + B / C * (D – E) b) Referring to question 4 (a), give the value of postfix expression by using the stack concept if provided: A=13, B=20, C=4, D=30, E=25Consider the following stack, which can be written as [70, 10, 50, 80, 20] i.e. the "top" of the stack is the first element in the list Consider the following code (written as pseudocode): myfunction( stack1 ) stack2 = createStack() while stack1 is NOT empty value = top(stack1) pop(stack1) while stack2 is NOT empty and top(stack2) > value push(stack1, top(stack2)) pop(stack2) push(stack2, value) print(stack2) // Prints the current stack as [element_1, element_2, ..., element_n] return stack2 From the answers below, select the correct output for the first 4 print statements if myFunction is executed with: myFunction( [ 70, 10, 50, 80, 20] )2. a) Using the stack diagram, convert the following infix expression to a postfix expression. A*(B + C* (D - E) ) / F b) Referring to question 2 (a), give the value of postfix expression by using the stack concept if provided: A=4, B=3, C=6, D=10, E=2 and F=4
- Machine organization The following operations are performed on a stack: PUSH A, PUSH B, POP, PUSH C, POP,POP,PUSH D, PUSH E, POP, PUSH F. What does the stack contain after each operation?L = {w ∈ {a, b}* | at least one prefix of w contains strictly more b’s than a’s.}.For example, baa, abb, abbbaa are in L, but aab, aabbab are not in L. a) Construct a PDA that accepts L by final state.b) Construct a PDA that accepts L by empty stack.3. a) Using the stack diagram, convert the following infix expression to a postfix expression. 4 + (9 – 3) / 2 b) Referring to question 3 (a), give the value of postfix expression by using the stack concept.
- 4.3 Refer to the code fragment below and convert the following Queue structure into a Stack structure. You should create a reference called S1 for the stack structure. Code: Queue Q1 = new LinkedList (); Q1.add("Sandra"); Q1.add (15); Q1.add (200); Q1.add ('#'); Q1. remove (); System.out.println(Q1); System.out.println(Q1.peek()); Q1.add("Mary"); System.out.println(Q1);Machine organization question The following operations are performed on a stack :PUSH A, PUSH B, POP, PUSH C, POP,POP,PUSH D, PUSH E, POP, PUSH F.What does the stack contain after each operation?Evaluate the following (postfix) expression using a stack. Assume A=1, B = 2 and C = 3. ABC+*CBA-+*
- Consider the following statements: stackType<int> stack; int x; Suppose that the input is: 14 45 34 23 10 5 -999 Show what is output by the following segment of code: stack.push(5); cin >> x; while (x != -999) { if (x % 2 == 0) { if (!stack.isFullStack()) stack.push(x); } else cout << "x = " << x << endl; cin >> x; } cout << "Stack Elements: "; while (!stack.isEmptyStack()) { cout << " " << stack.top(); stack.pop(); } cout << endl;Please with explanation \\\\\\\\\\\\\\\\\\\ JAVA\\\\\\\\\\\\\\\\\\\\\\\\\\ //21.3 * 3.1 / ( 14 + (6+2.1)^3) } //TODO public void convertToPostFix() { //create a stack of operators. //create Vector postFix //Go through inFix from 0 to size-1 //if current element is operand add it to postFix //if operator then as long as top of stack is operator of higher or equal //precedence pop it from stack and add it to postFix //push operator to stack //if open parenthesis push it to stack //if close parenthesis as long as top of stack is not open parenthesis, pop from //stack and add it to postFix. //pop the open parenthesis from stack (don't add it to postfix) //empty stack into postFix. } //TODO public double evaluate() { double result; return…Compilation Technique int f(int n) { int t, s; if (n < 2) return 1; s = f(n-1); t = f(n-2); return s+t; } 1. Create an Activation Tree to run the above program by calling f(5) !2. Make a stack and activation record for f, s and t !