15. An urn contains 5 red marbles and 3 white marbles. If two marbles are picked up at random, what is the probability that two marbles is red? 13/36 O 1/13 O 11/15 O 13/35 O 9 هذا السؤال مطلوب
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- Substitution ciphers are encryption/decryption algorithms that replace one letter or number with another. The first attested use of a substitution cipher in military affairs was by Julius Caesar, described by him in Gallic Wars (cf. Kahn pp83-84). In caesar cipher , you replace each letter by 3rd letter on. If it is out of bound (later than Z), then round to the head (letter A) and continue the shift. For example:meet me after the toga party PHHW PH DIWHU WKH WRJD SDUWB Please write a program in Java to implement the Caesar Cipher: a. Implement the encryption algorithm. Ask the user to input one all lower case normal sentence (called plaintext) using the nextLine method, and then output the encrypted text (called ciphertext). b. Implement the decryption algorithm. Ask the user to input one encrypted sentence (i.e. ciphertext) using the nextLine method, and then output the decrypted text (i.e. plaintext).Q_3 Let A be the set of all strings of decimal digits of length 5. For example 00312 and 19483 are two strings in A. You pick a string from A at random. What is the probability that the string has no 4 in it?A drawer contains 7 pair of socks where 8 socks are white, and 6 are red. In how many ways we can take 14 random socks out of the drawer so each sock is next to its matching pair. a. 441 ways b. 42 ways c. 1225 ways d. 70 ways
- import numpy as np # Given current stock pricecurrent_price = 163.02 # Simulate future stock pricesnum_samples = 1000 # You can adjust this number based on your needsgrowth_rate_samples = np.random.lognormal(mean=-0.8404, sigma=2.5, size=num_samples)future_prices = current_price * np.exp(growth_rate_samples) # Print or visualize the simulated future pricesprint(future_prices) i cant get an answer , im keeping errorsTrue or false set{(x,x2):x∈Z}canbeseeasafunctionZ→Q. set{(x2,x):x∈Z}canbeseeasafunctionZ→Q.X-Kingdom has trapped n number of soldiers of their opponent. They want to execute them. They created a strategy so that the prisoners will kill each other and at the end one prisoner will be alive and eventually released. As part of the process, they assigned each trapped soldier a sequence number starting from 1 and ending at n. If n = 5 and k = 2, then the safe position is 3. Firstly, the person at position 2 is killed, then person at position 4 is killed, then person at position 1 is killed. Finally, the person at position 5 is killed. So, the person at position 3 survives. If n = 7 and k = 3, then the safe position is 4. The people at positions 3, 6, 2, 7, 5, 1 are killed in order, and the person at position 4 survives. Input:n and k Output:Print the list of prisoners in reverse order from n to 1Then reverse the list to print it in correct order from 1 to nDisplay the position number who will survive. You must have to use circular doubly linked list for your solution.
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- Correct answer will be upvoted else Multiple Downvoted. Don't submit random answer. Computer science. every cell of the network contains a non-negative integer. Each turn, a player should play out every one of the accompanying activities all together. Pick a beginning cell (r1,c1) with non-zero worth. Pick a completing cell (r2,c2) to such an extent that r1≤r2 and c1≤c2. Lessening the worth of the beginning cell by some sure non-zero integer. Pick any of the most limited ways between the two cells and either increment, lessening or leave the upsides of cells on this way unaltered. Note that: a most limited way is one that goes through the most un-number of cells; all cells on this way barring the beginning cell, yet the completing cell might be altered; the subsequent worth of every cell should be a non-negative integer; the cells are changed freely and not really by a similar worth. On the off chance that the beginning and finishing cells are something very…there a N Book ,and M<N locations in a library .There are different ways in which these N books can be arranged in the location available.We will assume that the remaining book are put on the table The librarian ,Miss Boared-with-it-all goes about arranging these books in different ways all the time. You known,just to passthe time.Then she gets this bright idea to count the number the number of different ways that she can arrange all these books ,so that she hass something coll to fill into her appraised report.However , when she finally does computerthis number and starts to write it down ,she gets so lethargic she skips writing the trailing zero digits in the number .So now she wants you to WAP in java to count the number of digits she's skipped .Forexample 12340012000 ,then she only writes 12340012, i.e she skips writing the last three digit (three zeroes). So given N and M ,what's the number of digits that she does not write down? Input n M (two integer,single space separated)…How can I change my flower colors My code n=800;r=linspace(0,1,n);theta=linspace(0,2*pi,n);[R,THETA]=ndgrid(r,theta);% define the number of petals we want per cycle. Violets have 5!petalNum=5;x = 1 - (1/2)*((5/4)*(1 - mod(petalNum*THETA, 2*pi)/pi).^2 - 1/4).^2;% update the formula for phi to stop the spiralling effectphi = (pi/2)*exp(-2*pi/(8*pi));y = 1.95653*(R.^2).*(1.27689*R - 1).^2.*sin(phi);R2 = x.*(R.*sin(phi) + y.*cos(phi));X=R2.*sin(THETA);Y=R2.*cos(THETA);Z=x.*(R.*cos(phi)-y.*sin(phi));% color code for blueviolet RGB 138,43,226% Indigo rgb value (75,0,130)mapSize=20;blue_map=linspace(138,75,mapSize)';blue_map(:,2)=linspace(43,0,mapSize)';blue_map(:,3)=linspace(226,130,mapSize)';% and a pretty bit in the middlegold_map=[255 215 0; 250 210 0];% combine to form a full flower mapviolet_map=[gold_map; blue_map];% Now lets plot it and try and pick an attractive anglesurf(X,Y,Z,'LineStyle','none')colormap(violet_map/255)view([-12.700 81.200])